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Nikolay [14]
3 years ago
13

The price of gold has increased by 35% per year from 2000. In the year 2000, Harry bought a gold ring for $590. Which of the fol

lowing equations can be used to represent the price of the ring x years after 2000?
y = 590(1.35)x
y = 590(0.65)x
y = 35(0.41)x
y = 35(1.59)x
Mathematics
2 answers:
sammy [17]3 years ago
7 0

Answer:

y = 590(1.35)x

good luck

padilas [110]3 years ago
7 0

Answer:

Option first is correct.

Step-by-step explanation:

Here cost of gold ring in 2000  was = $590

Each year increase  = 35%  

in decimals  = 0.35

therefore cost after increase will be 1+0.35 = 1.35 of initial that is

                                                 

after 2 years =   590(1.35)^2

likewise after 3 years =590(1.35)^3

Similarly after x years it will be = 590(1.35)^x

Option 1 is correct!

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Endpoint 1: (-1,2)<br> Midpoint: (9,-6)<br> Endpoint 2=
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Answer:

(19 , -14)

Step-by-step explanation:

Find the distance in between each x & y for a coordinate.

Let: (x₁ , y₁) = (-1 , 2)

Let: (x₂ , y₂) = (9 , -6)

From x₁ ⇒ x₂: 9 - (-1) = 10

From y₁ ⇒ y₂: -6 - 2 = -8 = 8*

*Remember that distance cannot be negative, but for the sake of this question, we will leave it as -8.

The distance between the x points are in intervals of 10. The distance between the y points are in intervals of 8. Add 10 & subtract 8 to their respective numbers to get endpoint 2:

(9 (+ 10) , -6 (- 8)) = (19 , -14)

Endpoint 2 = (19 , -14)

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7 0
4 years ago
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Zinaida [17]

since we know the endpoints of the circle, we know then that distance from one to another is really the diameter, and half of that is its radius.

we can also find the midpoint of those two endpoints and we'll be landing right on the center of the circle.

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\bf ~~~~~~~~~~~~\textit{middle point of 2 points } \\\\ (\stackrel{x_1}{-4}~,~\stackrel{y_1}{-7})\qquad (\stackrel{x_2}{-2}~,~\stackrel{y_2}{-5})\qquad \qquad \qquad \left(\cfrac{ x_2 + x_1}{2}~~~ ,~~~ \cfrac{ y_2 + y_1}{2} \right) \\\\\\ \left( \cfrac{-2-4}{2}~~,~~\cfrac{-5-7}{2} \right)\implies \left( \cfrac{-6}{2}~,~\cfrac{-12}{2} \right)\implies \stackrel{center}{\boxed{(-3,-6)}} \\\\[-0.35em] ~\dotfill

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4 0
3 years ago
Read 2 more answers
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pantera1 [17]
Hi there!

If we know the perimeter of the lot, it's pretty easy to find the length and width. Since we know that the lot is a square, we know that all sides are the same. And there are four sides on a square. Using this information, we can get an equation: 60 = x + x + x + x. Then, we need to simplify and solve the equation: 60 = 4x | x = 15 feet. Therefore, the length and width of the lot is 15 feet.

Hope this helps!! :)
If there's anything else that I can help you with, please let me know!
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