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denis-greek [22]
3 years ago
12

The sum of two numbers is 48. Their difference is 38. Find the numbers.

Mathematics
2 answers:
Setler79 [48]3 years ago
4 0

Answer:

43 and 5

Step-by-step explanation:

Let's let the two unknown numbers be a and b.

Their sum is 48, therefore:

a+b=48

And their difference is 38. In other words:

a-b=38

We now have a system of equations. To solve, we can use substitution. First, add b to both sides in the second equation:

a=38+b

Substitute this into the first equation:

(38+b)+b=48

Combine like terms:

2b+38=48

Subtract 38 from both sides:

2b=10

Divide both sides by 2:

b=5

So, one of the numbers is 5.

The sum of them is 48. Therefore, the other number is 48-5 or 43.

So, our two numbers are 43 and 5.

And we're done!

sveticcg [70]3 years ago
3 0

Answer:

5 and 43

I hope this helps!

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A private and a public university are located in the same city. For the private university, 1038 alumni were surveyed and 647 sa
Snezhnost [94]

Answer:

The difference in the sample proportions is not statistically significant at 0.05 significance level.

Step-by-step explanation:

Significance level is missing, it is  α=0.05

Let p(public) be the proportion of alumni of the public university who attended at least one class reunion  

p(private) be the proportion of alumni of the private university who attended at least one class reunion  

Hypotheses are:

H_{0}: p(public) = p(private)

H_{a}: p(public) ≠ p(private)

The formula for the test statistic is given as:

z=\frac{p1-p2}{\sqrt{{p*(1-p)*(\frac{1}{n1} +\frac{1}{n2}) }}} where

  • p1 is the sample proportion of  public university students who attended at least one class reunion  (\frac{808}{1311}=0.616)
  • p2 is the sample proportion of private university students who attended at least one class reunion  (\frac{647}{1038}=0.623)
  • p is the pool proportion of p1 and p2 (\frac{808+647}{1311+1038}=0.619)
  • n1 is the sample size of the alumni from public university (1311)
  • n2 is the sample size of the students from private university (1038)

Then z=\frac{0.616-0.623}{\sqrt{{0.619*0.381*(\frac{1}{1311} +\frac{1}{1038}) }}} =-0.207

Since p-value of the test statistic is 0.836>0.05 we fail to reject the null hypothesis.  

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3 years ago
Please help I don’t understand
nikitadnepr [17]

Answer:

5 people

Step-by-step explanation:

For each people Ms Hernandez bring to the zoo, she will pay $15.50, so if she go alone, 1×15.50, if she go with one person, 2×15.50, with three 3×15.50, and keep growing this way. The price each person pay is constant and equal to 15.50, and what will determine the final price is the number of people. Also remember that she always will have to pay $ 10 on parking, so you can write an equation with this:

15.50x +10 = y, as x being the number of people and y being the final price.

She have $100, so this is the max she can spend. Two know the number of people she can bring to the zoo, put 100 in place of y and find the value of x:

15.50x + 10 = 100

15.50x = 100 - 10

15.50x = 90

x = 90/15.50

x = 5.8

But there's no way to bring 0.8 person, so the max she can bring are 5 people, including her

5 0
3 years ago
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Which equation represents the line that passes through the points (1, 3) and (-2,5)?
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Step-by-step explanation:

7 0
3 years ago
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Ymorist [56]

Answer:

1051 .55 {mm}^{2}

Step-by-step explanation:

Find the area of the square - area of 4 sectors

We'll use the formula to find one sector area

a =  \frac{1}{2}  \times  {r}^{2}  \times x

where r is the radius of one sector and x is the angle in radians

Since each angle is in a square, the angle of the sectors is 90 degrees.

Convert degrees to radians

90 =  \frac{1}{2} \pi \: rad

The radius of one sector is given by 70mm/2=35mm

One sector area:

\frac{1}{2}  \times {35}^{2}  \times  \frac{1}{2} \pi = 306.25\pi

Area of all 4 sectors:

4 \times 306.25\pi = 1225\pi

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Hence, Area of square - 4 Sectors:

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