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tekilochka [14]
3 years ago
6

Point A is at -7, -3. There are 12 points between A and B. What are possible coordinates for point B?

Mathematics
1 answer:
Finger [1]3 years ago
8 0

Answer:

(5,9)

(-19, - 15)

(5, - 15)

(-19, 9)

Step-by-step explanation:

Given that :

Coordinate of point A = - 7, - 3

Number of points between point A and B = 12

Possible coordinate of point B

Possible coordinates of point B:

(-7, - 3) + 12 = (5, 9)

(-7, - 3) - 12 = (-19, - 15)

(-7, - 3) = (-7 +12, -3 - 12) = (5, - 15)

(-7, - 3) = (-7 - 12, - 3 + 12) = (-19, 9)

Hence possible coordinates of be are :

(5,9)

(-19, - 15)

(5, - 15)

(-19, 9)

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The ratio of credit card sales to cash sales at a store was 8:3. If the store had 144 cash sales, how many more credit card sale
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Answer:

There were 240 more credit card sales than cash sales.

Step-by-step explanation:

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4 0
3 years ago
Choose the solution(s) of the following system of equations x2 + y2 = 6 x2 – y = 6
ElenaW [278]
<h2>Answer</h2>

x=\sqrt{6}, y=0\\ x=-\sqrt{6} , y=0\\x=\sqrt{5} , y=-1\\x=-\sqrt{5} , y=-1

Or as ordered pairs: (\sqrt{6} ,0),(-\sqrt{6} ,0),(\sqrt{5} ,-1),(-\sqrt{5} ,-1)

<h2>Explanation</h2>

Lets solve our system of equations  step by step

x^2+y^2=6 equation (1)

x^2-y=6 equation (2)

1. Solve for x^2 in equation (2)

x^2-y=6

x^2=6+y equation (3)

2. Replace equation (3) in equation (1) and solve for y

x^2+y^2=6

6+y+y^2=6

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y(y+1)=0

y=0 or y=-1

3. Replace the values of y in equation (3) and solve for x

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- For y=-1

x^2=6+y

x^2=6-1

x^2=5

x=\sqrt{5} or x=-\sqrt{5}

So, the solutions of our system of equation are:

x=\sqrt{6}, y=0\\ x=-\sqrt{6} , y=0\\x=\sqrt{5} , y=-1\\x=-\sqrt{5} , y=-1

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