Why does the sum of -4 and 3 complain more than the sum of -3 and 5?
1 answer:
You might be interested in
Answer:
6m
Step-by-step explanation:
the side of first square = 3 m
area of first square = 3^2= 9 m^2
let the side of second square = x m
since diagonal of first square = x m as per the question
in a square each angle is 90 degree
therefore by applying pythagorus theorem ,
diagonal ^2 = side^2 + side ^2
diagonal^2 = 3^2+3^2=9+9
DIAGONAL= square root of 18
diagonal= 3 m = side of second square
therefore in second square ,
one angle is 90 degree , therefore by applying pythagorue theorem
diaqonal^2 = side ^2 + side ^2 = (3)^2 + ( 3
)^2
diagonal ^2 = 18 + 18
diagonal = square root of 36
therefore diagonal of second square is 6m
hope it helps you... please mark me as the brainliest..
Answer:
The price of each movie is $2.25
The price of each video games is $5.41
Step-by-step explanation:
Given as :
Miguel rented 5 movies and 3 video games for a total cost = $27
Next day Miguel rented 2 movies and 6 video games for a total cost = $36
Let The cost of each movie = $m
And The cost of each video game = $v
Now, According to question
5 m + 3 v = 27 .....1
2 m + 6 v = 36 ...........2
Now, solving the equation
2 × (5 m + 3 v) - (2 m + 6 v) = 2 × 27 - 36
Or, 10 m + 6 v - 2 m - 6 v = 54 - 36
Or, (10 m - 2 m) + (6 v - 6 v) = 18
Or, 8 m + 0 = 18
∴ m = =
i.e m = $2.25
So, The price of each movie = m = $2.25
Again, put the value of m into eq 2
So, 2 × 2.25 + 6 v = 36
Or, 4.5 + 6 v = 36
Or, 6 v = 36 - 4.5
Or, 6 v = $32.5
∴ v =
i.e v = $5.41
So, The price of each video games = v = $5.41
Hence, The price of each movie is $2.25 and
The price of each video games is $5.41 Answer