Circle: x^2+y^2=121=11^2 => circle with radius 11 and centred on origin.
g(x)=-2x+12 (from given table, find slope and y-intercept)
We can see from the graphics that g(x) will be almost tangent to the circle at (0,11), and that both intersection points will be at x>=11.
To show that this is the case,
substitute g(x) into the circle
x^2+(-2x+12)^2=121
x^2+4x^2-2*2*12x+144-121=0
5x^2-48x+23=0
Solve using the quadratic formula,
x=(48 ± √ (48^2-4*5*23) )/10
=0.5058 or 9.0942
So both solutions are real and both have positive x-values.
Option C: 1 is the simplification of the expression 
Explanation:
The given expression is 
We need to simplify the given expression.
<u>Simplification:</u>
To simplify the given expression, let us apply the exponent rule,
where 
Thus, the the exponent rule
means that any value (except zero) to the power of zero is equal to one.
Thus, the expression
becomes,

Therefore, the simplified expression is 1
Hence, Option C is the correct answer.
Answer:
3b -
b
Step-by-step explanation:
Let the number be "b"
So the expression would be:
3b -
b
311,225,823,387,830,850,069
Oof
Hello!
The answer to your problem is: 
<u>Simplify both sides of the equation</u>


<u>Subtract 2/3x from both sides</u>


<u>Subtract 2 from both sides</u>


<u>Multiply both sides by 3/(-26)</u>

<u>Get your answer</u>

Hope This Helps!