Hi there!
Since ST is a tangent to the circle, we can use the relationship: tangent squared = external secant segment x entire secant segment.
WORK:
(I will be using x in place of ST)
x^2 = 7(23 + 7)
x^2 = 7(30)
x^2 = 210
x = squareroot(210) or approximately 14.5 inches
Hope this helps!! :)
9514 1404 393
Answer:
- 2nd force: 99.91 lb
- resultant: 213.97 lb
Step-by-step explanation:
In the parallelogram shown, angle B is the supplement of angle DAB:
∠B = 180° -77°37' = 102°23'
Angle ACB is the difference of angles 77°37' and 27°8', so is 50°29'.
Now, we know the angles and one side of triangle ABC. We can use the law of sines to solve for the other two sides.
BC/sin(A) = AB/sin(C)
AD = BC = AB·sin(A)/sin(C) = (169 lb)sin(27°8')/sin(50°29') ≈ 99.91 lb
AC = AB·sin(B)/sin(C) = (169 lb)sin(102°23')/sin(50°29') ≈ 213.97 lb
Answer:
You would get tails 75 times, or 75:200
Step-by-step explanation:
5:8 = x:200
multiply 8 by 25 to get 200
multiply 5 by 25 to get x (125)
Probability to get heads is 125 so subtract 200 by 125
200 - 125 = 75
Answer:
m=-14 I hope this helps u
Step-by-step explanation:
So hmm notice the picture below
the pyramid itself, is really, just one regular hexagon, at the bottom
and 6 triangles, stacked up at each other at the edges
now, if you just get the area of the regular hexagon, and the 6 triangles, add them up, that'd be the total surface area of the pyramid then

now, for the triangles, well, area of a triangle is 1/2 bh, as you'd know, and you have both