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Ratling [72]
3 years ago
14

Consider a data set containing the following values:

Mathematics
1 answer:
d1i1m1o1n [39]3 years ago
5 0

Answer:

a. 125.0714; 11.1835.

b. 109.4375; 10.4612.

Step-by-step explanation:

Given the following data;

70, 65, 71, 78, 89, 68, 50, 75.

<em>Mean = 70.75</em>

The deviation for the mean of the data is -0.75, -5.75, 0.25,7.25,18.25,-2.75,-20.75, and 4.25.

We would then find the square of this deviation;

=(-0.75)^2+(-5.75)^2+( 0.25)^2+(7.25)^2 +(18.25)^2+(-2.75)^2+(-20.75)^2 +(4.25)^2

=0.5625+33.0625+0.0625+52.5625+333.0625+7.5625+430.5625+18.0625

= 875.5

Next is to find the population variance;

V = \frac{875.5}{8}

<em>Variance, V = 109.4375 </em>

The population standard deviation is the square root of the population variance;

Sd = \sqrt{109.4375}

<em>Standard deviation, Sd = 10.4612</em>

To find the sample variance;

V = \frac{875.5}{8-1}

V = \frac{875.5}{7}

<em>Variance, V = 125.0714</em>

The sample variance is;

Sd = \sqrt{125.0714}

<em>Standard deviation, Sd = 11.1835</em>

<em>Therefore, </em>

<em>a. The sample variance is 125.0714 and the sample standard deviation is 11.1835.</em>

<em>b. If this is a population data, the population variance is 109.4375 and the population standard deviation is 10.4612.</em>

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Answer:

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Step-by-step explanation:

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so it would be:

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Step-by-step explanation:

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