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Fudgin [204]
3 years ago
15

Suppose you select 2 letters at random from the word compute without replacement. Find each probability. P(2 vowels)

Mathematics
1 answer:
Troyanec [42]3 years ago
8 0

Answer:

1/7

Step-by-step explanation:

The word "compute" has 7 letters, 3 of which are vowels.

The probability that the first letter is a vowel is 3/7.

There's no replacement, so there are 6 letters left, 2 of which are vowels.

The probability that the second letter is a vowel is 2/6.

The probability of 2 vowels is therefore:

P = (3/7) (2/6)

P = 1/7

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Answer:

x=-32/29

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Step-by-step explanation:

3x+4y=36 Equation 1

-5x+3y=35 Equation 2

Multiplying equation 1 with 3 (value before y in equation 2) and equation 2 with 4 (value before y in equation 1) we obtain equations 3 and 4 as follows

9x+12=108 equation 3

-20x+12y=140 equation 4

Subtracting equation 3 from equation 4 we obtain

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To find the value of y, we substitute the value of x into equation 2 as initially given in the equation

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3 years ago
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3 years ago
Prove the statement holds for all positive integers:<br><br> 2 + 4 + 6 + ... + 2n = n² + n
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