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4 years ago

Estimate the following difference by rounding each number to the nearest hundred.

Mathematics

2 answers:

Arte-miy333 [17]4 years ago

8 0

1348.5 rounds down to 1300 because 4 is less than 5
567.21 rounds up to 600 because 6 is greater than 5
1300-600=700

slavikrds [6]4 years ago

5 0

D, is the answer. :)

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There are 16 entrees available at a restaurant. From these, Archie is to choose 6 for his party. How many groups of 6 entrees ca

goblinko [34]

Answer: 8008

Step-by-step explanation:

Total entrees = 16

Number of entrees to choose = 6

Since order does not matter , so we combinations .

Number of combinations to choose r things out of n = $C(n,r)=\dfrac{n!}{r!(n-r)!}$

Then, total ways to choose 6 entrees = $C(16,6)=\dfrac{16!}{6!10!}$

$=\dfrac{16\times15\times14\times13\times12\times11\times10!}{(720)10!}\\\\= 8008$

Hence, the required number of ways= 8008

4 0

3 years ago

What’s the distance between (8,-5 ) and (6,4)

Ierofanga [76]

Answer:

Step-by-step explanation:

d^2=(x2-x1)^2+(y2-y1)^2

d^2=(6-8)^2+(4+5)^2

d^2=4+81

d^2=85

d=(85)^(1/2)

d=9.22 (rounded to nearest hundredth)

6 0

3 years ago

Read 2 more answers

K=1/2 mv squared, determined m when v=30 and k=4500.

WITCHER [35]

Given the expression:

$\text{ k = }\frac{1}{2}mv^2$

At v = 30 and k = 4,500 , let's determine m.

$\text{ k = }\frac{1}{2}mv^2$ $\frac{2k}{v^2}\text{ = m }\rightarrow\text{ m = }\frac{2k}{v^2}$

We get,

$\text{ m = }\frac{2k}{v^2}$ $\text{ = }\frac{2(4,500)}{(30)^2}$ $\text{ = }\frac{9,000}{900}$ $\text{ m = 10}$

Therefore, m = 10.

7 0

2 years ago

Malcolm bar is a toggle for a 1.79 and milk for 1.29 about how much money does he spend

jeka94

1.79 + 1.29 if i’m understanding the question right

that would be 3.08

7 0

3 years ago

For the function F defined by F(x)=x^2-2x+4 find F(2b-1).

Leni [432]

Answer:

F(2b-1) = 4b² - 6b + 4

Step-by-step explanation:

Replace all the x with 2b-1

F(x) = x² - 2x + 4

F(2b-1) = (2b-1)² - 2(b) + 4

= 4b² - 4b + 1 - 2b + 4

= 4b² - 6b + 4

5 0

3 years ago