The average honey bee can travel 10.5 feet per second. How many feet can the honeybee travel in 3.7 seconds?
1 answer:
Answer:
The honey bee would go 38.85 feet if it was traveling at 10.5 feet per second for 3.7 seconds
Step-by-step explanation:
Take the speed the bee is flying (10.5) and times it by the time (3.7) and you get 38.85 which is the answer. 38.85 feet
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To solve for time taken we use the compound formula:
A=P(1+r/100*n)^(n*t)
where:
A=future value
P=principle
r=rate
t=time
n=number of terms
6265=4000(1+7.5/(12*100))^(12t)
solving for t we get
1.56625=1.00625^12t
12t=72.0136
t=6.00 years
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