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PolarNik [594]
2 years ago
6

3. Last year, the numbers of skateboards produced per day at a certain factory were normally distributed with a mean of 20,500 s

kateboards and a standard deviation of 55 skateboards.
(a) On what percent of the days last year did the factory produce 20,555 skateboards or fewer?
(b) On what percent of the days last year did the factory produce 20,610 skateboards or more?
(c) On what percent of the days last year did the factory produce 20,445 skateboards or fewer?
Mathematics
1 answer:
Oxana [17]2 years ago
4 0
Let x be a random variable representing the number of skateboards produced
a.) P(x ≤ 20,555) = P(z ≤ (20,555 - 20,500)/55) = P(z ≤ 1) = 0.84134 = 84.1%

b.) P(x ≥ 20,610) = P(z ≥ (20,610 - 20,500)/55) = P(z ≥ 2) = 1 - P(z < 2) = 1 - 0.97725 = 0.02275 = 2.3%

c.) P(x ≤ 20,445) = P(z ≤ (20,445 - 20,500)/55) = P(z ≤ -1) = 1 - P(z ≤ 1) = 1 - 0.84134 = 0.15866 = 15.9%
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From 1985 to 2007, the number B B of federally insured banks could be approximated by B ( t ) = − 329.4 t + 13747 B(t)=-329.4t+1
Romashka-Z-Leto [24]

Answer:

12100

Step-by-step explanation:

If the number B of federally insured banks could be approximated by B ( t ) = − 329.4 t + 13747 from 1985 to 2007 where t = 0 correspond to year 1985

In order to determine the amount of federally insured banks that were there in 1990, we will first calculate the year range from initial time 1985 till 1990

The amount of time during this period is 5years. Substituting t = 5 into the modeled equation will give;

B ( t ) = − 329.4 t + 13747

B(5) = -329.4(5) + 13747

B(5) = -1647+13747

B(5) = 12100

This shows that there will be 12100 federally insured banks are there in the year 1990.

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3 years ago
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<h2 />

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5 0
2 years ago
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Optimization problem: what are the dimensions of the lightest open-top right circularcylindrical can that will hold a volume of
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So Volume of cylinder is pi*r^2*h = 1,000 

Then lightest one means you have the smallest surface area. Which is one base and then the area of the surface. SA = pi*r^2 + 2pi*r*h 

So now you have 2 equations, so: 

h = 1,000/(pi*r^2) 
So then SA = pi*r^2 + 2pi*r*(1,000/(pi*r^2) = pi*r^2 + 2,000/r 

Derivative of SA is then 2pi*r -2,000/r^2. Set to 0 

2pi*r-2,000/r^2 =0 --> 2pi*r^3 = 2,000 --> r^3 = 1,000/pi --> r = 10/pi^(1/3) 

Now go back to the volume function: pi*r^2*h =1,000 --> 1,000/(pi*100/pi^(2/3)) = h 
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