Answer:
Recycle and dispose of trash properly. Marine debris can be harmful to coral reefs. ...
Minimize use of fertilizers. ...
Use environmentally-friendly modes of transportation. ...
Reduce stormwater runoff. ...
Save energy at home and at work. ...
Be conscious when buying aquarium fish. ..
Explanation:
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Answer:
Na + H2O NaOH + H2 is the ans
The predicated frequency of homozygous dominant rats at are: 0.11 (Option A). See the explanation below.
<h3>What is a
homozygous dominant rat?</h3>
A homozygous organism has two copies of the same allele for a gene.
If an organism has two copies of the same dominant allele, it is homozygous dominant; if it has two copies of the same recessive gene, it is homozygous recessive.
<h3>
What is the justification of the above answer?</h3>
Note that the total population of rats is: 200
Number of rats with brown fur = 112
The frequency of brown fur rats thus,
112/200
= 0.56
Note that it is also stated that the brown fur rats are dominant in relation to the gray fur rats. Thus, in accordance to Hardy Weinberg's equation, the frequency of the dominant rats is depicted as: p²
Thus:
p² + 2pq = 0.56
Hence, the frequency of the the Homozygous recessive gray rats is given as:
p² + q² + 2pq = 1
q² = 1 - 0.56
q² = 0.44
q = 0.663
P = 1-q
= 1 - 0.663
= 0.337
Thus the frequency of the homozygous dominant rats is:
p²
= 0.337²
= 0.1135
≈ 0.11
Therefore the correct answer is A.
Learn more about homozygous organism at;
brainly.com/question/10253387
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Answer:
Because the two-point analysis underestimates the actual distance between A and B for not taking into consideration all the possible crossing-overs. The most accurate result is the one thrown by the three-point analysis.
Explanation:
When calculating genetic distances, we might notice a difference when using a two-point analysis and when making a three-point analysis. Their results are different. This difference is because distances between genes are not completely additive. They might vary. We can notice this difference in the exposed example, in which the map distance between <em>A and B when using a two-point analysis equals 26 map units</em>. However, <em>when using a three-point analysis, it equals 33 map units</em>. The <em>addition of distances from A to C and from C to B is 33 and not 26</em>.
Calculating the recombination frequency between the two genes located in the extremes and far apart from each other<u> underestimate </u>the actual genetic distances between them, because there might occur other crossing-overs that were not detected. So, when calculating the genetic distance from A to B, we probably will not consider the occurrence of a double recombinant between them, and we might sub-estimate the actual distance. In between A and B many simple and double-crossing over might occur, and might not be detected by the two-point analysis.
The relationship between the actual map distance (number of crossing overs) and the recombination frequency between two loci is not lineal. The farther apart the two genes are, the worse is the distance estimation.
The most accurate analysis is the three-point one that is based on the addition of distances between every two genes.
Answer:
2n
Explanation:
All the phases double the cells
