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Zinaida [17]
4 years ago
15

Many people believe that the daily change of price of a company's stock on the stock market is a random variable with mean 0 and

variance 2. That is, if Yn represents the price of the stock on the n-th day, then Yn = Yn-1 + Xn, n > 1 where X1, X2, . . . are independent and identically distributed random variables with mean 0 and variance 2. Suppose that the stock's price today is 100. If 2 = 1, use CLT to approximate the probability that the stock's price will exceed 105 on the 10-th day?
Mathematics
1 answer:
Tomtit [17]4 years ago
8 0

Answer:

Step-by-step explanation:

We can use normal aproximation, assuming that the random variables are a lot of that means the sample size is large.

P(x>105) = P(z>\frac{105-100}{1})=P(z>5)

Using the normal distribution table,

P(z>5) = 0.00005

Hence, we can conclude that the probability that the stock’s price will exceed 105 after 10 days is very small.

Hope this helps!

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3 years ago
Find value of x such that the data set has a mean of 105: 99, 119, 106, 112; 108
Marizza181 [45]
I'm assuming that x is part of the data set, and, with x, the mean equals 105. To find the value of x, you must add all the data values together to get 544+x (you still don't know what x equals). Then put 544+x over how many days values there are, including x (there are 6). You should have 544+x/6. Now, as this is how you would calculate the mean if you knew what x was equal to, you must set it equal to the mean, since you know what it is (105). You should now have 544+x/6 = 105. You have your equation set up--now you just have to solve it. I would multiply by 6 on both sides to get rid of the 6 on the left side. You would then have 544+x = 630. I would finally subtract 544 from both sides to get x = 86. Your final answer is x = 86.
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