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padilas [110]
3 years ago
6

The radius AND height of a cylinder are each doubled. What is the new volume?

Mathematics
1 answer:
Naya [18.7K]3 years ago
7 0

The volume of a cylinder is given by

V = \pi hr^2

Let h\mapsto 2h and r\mapsto 2r

The new volume becomes

V = \pi(2h)(2r)^2 = \pi\cdot 2h \cdot 4r^2 = 8\pi hr^2

So, the new volume is 8 times the original volume. In fact, volume scales linearly with the height and quadratically with the radius.

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PLEASE HELP ME WITH MY MATH
emmainna [20.7K]

Oh my gosh,

I need an answer for that as well..

4 0
2 years ago
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Re-write the quadratic function below in Standard Form<br> y= –2(x + 5)(x – 4)
Naddik [55]

Answer:

y = - 2x² - 2x + 40

Step-by-step explanation:

Standard form of a quadratic is y = ax² + bx + c : a ≠ 0

Given

y = - 2(x + 5)(x - 4) ← expand factors using FOIL

  = - 2(x² - 4x + 5x - 20)

  = - 2(x² + x - 20) ← distribute parenthesis by - 2

  = - 2x² - 2x + 40 ← in standard form

6 0
3 years ago
Please help me!!!!<br> WILL MARK BRAINLYIST
Katen [24]

Answer:

x=5.4

Step-by-step explanation:

-2.3(x - 1.2) = -9.66

Distribute -2.3

-2.3x + 2.76 = -9.66 (2 negatives make positive)

Subtract the constant (2.76)

-2.3x = -12.42

Divide by coefficient on both sides to get:

x=5.4

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(Pretty sure)

3 0
3 years ago
In the figure, ray OB bisects ∠TOY.
Levart [38]

<u><em>Answer:</em></u>

∠BOY = 38°

<u><em>Explanation:</em></u>

<u>From the diagram, we can note that:</u>

m∠TOY = m∠TOB + m∠BOY ...................> equation I

We are given that ray OB bisects the angle

<u>Therefore:</u>

m∠TOB = m∠BOY

<u>Substitute in equation I:</u>

m∠TOY = m∠TOB + m∠TOB = 2m∠TOB ............> equation II

<u>We are given that:</u>

m∠TOY = 8x-36

m∠TOB = x+24

<u>Substitute with the givens in equation II and solve for x:</u>

m∠TOY = 2m∠TOB

8x - 36 = 2(x + 24)

2(4x-18) = 2(x+24)

4x - 18 = x + 24

3x = 42

x = 14

<u>This means that:</u>

m∠TOB = x + 24 = 14 + 24 = 38°

<u>Since </u>

m∠TOB = m∠BOY

<u>Therefore:</u>

m∠BOY = 38°

<u>Check:</u>

m∠TOY = 8x - 36 = 8(14) - 36 = 76° which is twice m∠TOB

Hope this helps :)

8 0
4 years ago
(x+3)(3x² - 5x - 10) multiply polynomial
brilliants [131]

Answer:

  • \boxed{\sf{3x^3+4x^2-25x-30}}

Step-by-step explanation:

\underline{\text{SOLUTION:}}

To isolate the term of x from one side of the equation, you must multiply by a polynomial.

\underline{\text{GIVEN:}}

:\Longrightarrow: \sf{(x+3)(3x^2 - 5x - 10)}

<u>You have to solve with parentheses first.</u>

:\Longrightarrow \sf{x\cdot \:3x^2+x\left(-5x\right)+x\left(-10\right)+3\cdot \:3x^2+3\left(-5x\right)+3\left(-10\right)}

<u>Solve.</u>

\sf{x*3x=3x^3}

x(-5x)=-5x²

\sf{x(-10)=-10x}

3*3x²=9x²

3(-5x)=-15x

3(-10)=-30

<u>Then, rewrite the problem down.</u>

\sf{3x^3-5x^2-10x+9x^2-15x-30}

<u>Combine like terms.</u>

\Longrightarrow: \sf{3x^3-5x^2+9x^2-10x-15x-30}

<u>Add/subtract the numbers from left to right.</u>

-5x²+9x²=4x²

\Longrightarrow: \sf{3x^3+4x^2-10x-15x-30}

<u>Solve.</u>

\sf{-10x-15x=-25x}

<u>Then rewrite the problem.</u>

\Longrightarrow: \boxed{\sf{3x^3+4x^2-25x-30}}

  • <u>Therefore, the correct answer is 3x³+4x²-25x-30.</u>

I hope this helps! Let me know if you have any questions.

6 0
3 years ago
Read 2 more answers
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