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padilas [110]
3 years ago
6

The radius AND height of a cylinder are each doubled. What is the new volume?

Mathematics
1 answer:
Naya [18.7K]3 years ago
7 0

The volume of a cylinder is given by

V = \pi hr^2

Let h\mapsto 2h and r\mapsto 2r

The new volume becomes

V = \pi(2h)(2r)^2 = \pi\cdot 2h \cdot 4r^2 = 8\pi hr^2

So, the new volume is 8 times the original volume. In fact, volume scales linearly with the height and quadratically with the radius.

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Answer:

  \dfrac{p^2+9p+2}{p^2-49}

Step-by-step explanation:

Problems like this require that you recognize that the denominator of the right term is a factor of the denominator of the left term. That is, you're supposed to know how to recognize and factor the difference of two squares.

  \dfrac{5-p}{49-p^2}+\dfrac{p+1}{p-7}=\dfrac{p-5}{p^2-49}+\dfrac{p+1}{p-7}\\\\=\dfrac{p-5}{(p-7)(p+7)}+\dfrac{p+1}{p-7}\cdot\dfrac{p+7}{p+7}\\\\=\dfrac{(p-5)+(p+1)(p+7)}{(p-7)(p+7)}=\dfrac{p-5+p^2+8p+7}{p^2-49}=\dfrac{p^2+9p+2}{p^2-49}

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Step-by-step explanation:

so sorry if this is wrong, but i think thats it

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