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melamori03 [73]
3 years ago
11

Abcd is a trapezium in which ablldc​

Mathematics
1 answer:
Anna11 [10]3 years ago
7 0

Answer:

Step-by-step explanation:

Draw OE parallel to AB and CD.

In  ABD, OE || AB

By Basic Proportionality theorem,

... (i)

In  CDA, OE || CD

By Basic Proportionality theorem,

... (ii)

From (i) and (ii), we get,

Or,  

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The average (arithmetic mean) of y numbers is x. if 30 is added to the set of numbers, then the average will be x - 5. what is t
Anastasy [175]
Given,

AM of y numbers = x.

Let the sum of y numbers be s.

AM of y numbers = x

\frac{s}{y} = x

s = y*x

Given, when 30 is added to the y numbers, the AM becomes x - 5.

\frac{s + 30}{y + 1} = x - 5

\frac{y*x + 30}{y +1} = x - 5


y*x + 30 = (x -5)( y +1)

y*x + 30 = y*x + x - 5y -5

5y = x - 5 -30 = x - 35


y =  \frac{x -35}{5} 
8 0
4 years ago
a new car is purchased for 207000 dollars. the value of the car depreciates at 11% per year. what will the value of the car be,
kicyunya [14]
Depreciation of 11% per year means that the price is multiplied by 89% (0.89) every year. Do this 11 times or use exponents

Final price:
207000*(0.89^11) = 57446.083
7 0
3 years ago
Can anyone solve this question??? plss plsss its my request to all if any one can solve this question I will mark him/ her the b
almond37 [142]

Answer:

a) ∠EAB = 180° - 90° - 30° = 60°

∠EBA = 180° - 90° - 60° = 30°

a) ∠EBA = 30°

b) ∠DCA = 180° - 90° - 30° = 60°

∠EBA ≅ ∠DAC, ∠EAB ≅ ∠DCA, ∠AEB ≅ ∠CDA

ΔEBA ≅ ΔDAC because of the AAA postulate

c) EB ≅ DA, EA ≅ DC, AB ≅ CA

d) AB = CA     given

sin ∠EAB = EB/AB       (sin 60°)   EB = (0.8660)AB

cos ∠EAB = EA/AB      (cos 60°)  EA = (0.5)AB

cos ∠DAC = AD/CA     (cos 30°)  AD = (0.8660)CA

sin ∠DAC = CD/CA      (sin 30°)   CD = (0.5)CA

ED = EA + AD

ED = (0.5)AB + (0.8660)CA

since AB = CA,  ED = 1.366CA

since EB = (0.8660)AB and AB = CA, then EB = 0.866CA

since CD = 0.5CA,

EB  + CD = 0.866CA + 0.5CA = 1.366CA

EB + CD = 1.366CA

1.366CA = 1.366CA

Proof: ED = EB + CD

7 0
3 years ago
Its about differention ​
nika2105 [10]
Had -9-x^2
———
x^2

adh (-9-x^2)
——————-
x^2

-9adh-adhx^2
———————
x^2

9adh+adhx^2
- ———————
x^2

Hope this helps
6 0
3 years ago
Special right triangles 45-45-90 &amp; 30-60-90 formula!!<br> finding missing side lengths
nordsb [41]

The formula you need to know is that the side opposite of the 30° angle is always half the hypotheneus. For example in question 2 X should be 6 since 3 is opposite side of the angle 30°. In a 45 45 90 triangle, it is important to know that the straight sides are always the same length (since they are the same angle). For example in question 9, v is also 9√2.

When you have two sides, you can figure out the third side with a² + b² = c² since they are all right triangles. Good luck

4 0
3 years ago
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