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Tomtit [17]
3 years ago
12

Use multiplication to find 5% of 500

Mathematics
1 answer:
exis [7]3 years ago
3 0

Answer: 5% of 500 is 1

Step-by-step explanation:

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Abby can buy individual songs for $1.00 to download, or she can
Taya2010 [7]

The solution to the inequalities x + 8y ≤ 50, x ≤ 30, y > 2 is the darker region shown on the graph.

<h3>What is an equation?</h3>

An equation is an expression that shows the relationship between two or more variables and numbers.

Let x represent the number of individual songs and y represent the number of albums, hence:

x + 8y ≤ 50   (1)

x ≤ 30    (2)

y > 2   (3)

The solution to the inequalities x + 8y ≤ 50, x ≤ 30, y > 2 is the darker region shown on the graph.

Find out more on equation at: brainly.com/question/2972832

#SPJ1

3 0
1 year ago
Using the table below, complete and explain the process used for each step in solving the equation. 4c+ 12-2c = 5c - 3​
Oduvanchick [21]

Answer:

c=3

Step-by-step explanation:

4c+12-2c=5c-3  1. combine like terms

2c+12=5c-3    2. -5c on both sides

-3c+12=3      3. -12 on both sides

-3c=-9       4. /-3 on both sides

c=3

6 0
2 years ago
Help help help help pls
Monica [59]

Answer:

\theta = 82.2^\circ

Step-by-step explanation:

Let \  \angle BAC = \theta

Opposite = BC ,

Adjacent = AB = x = 3 ,

Hypotenuse = AC = y = 22

<em><u>Using trigonometric ratios.</u></em>

sin \theta = \frac{opposite}{hypotenuse }\\\\cos \theta = \frac{adjacent}{hypotenuse}\\\\tan \theta = \frac{opposite}{adjacent}

Since we have adjacent and hypotenuse we use cosine's  ratio

to find the angle.

           cos \theta = \frac{x}{y} = \frac{3}{22} \\\\\theta = cos^{-1} \frac{3}{22} = 82.16 = 82.2^\circ

6 0
2 years ago
Which equation has no solition
DochEvi [55]
Every equation does?
6 0
3 years ago
Read 2 more answers
If a truck travels 160 miles on 20 gallons of gas, how many gall travel 400 miles?
Olenka [21]

Step-by-step explanation:

160 miles = 20 gallons

400 miles = x gallons

160 × x = 20 × 400

x = 8, 000/160

x = 50 gallons

5 0
3 years ago
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