<h3>
Answer: 11/20</h3>
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Work Shown:
x = unknown horizontal length
1/5 = 0.2
Perimeter = 2*(width + length)
P = 2*(0.2 + x)
P = 0.4 + 2x
Set this equal to the given perimeter of 1 & 1/2 = 1.5 and solve for x
0.4 + 2x = 1.5
2x = 1.5-0.4
2x = 1.1
x = (1.1)/2
x = 0.55
x = 55/100
x = (5*11)/(5*20)
x = 11/20
Explanation:
A sequence is a list of numbers.
A <em>geometric</em> sequence is a list of numbers such that the ratio of each number to the one before it is the same. The common ratio can be any non-zero value.
<u>Examples</u>
- 1, 2, 4, 8, ... common ratio is 2
- 27, 9, 3, 1, ... common ratio is 1/3
- 6, -24, 96, -384, ... common ratio is -4
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<u>General Term</u>
Terms of a sequence are numbered starting with 1. We sometimes use the symbol a(n) or an to refer to the n-th term. The general term of a geometric sequence, a(n), can be described by the formula ...
a(n) = a(1)×r^(n-1) . . . . . n-th term of a geometric sequence
where a(1) is the first term, and r is the common ratio. The above example sequences have the formulas ...
- a(n) = 2^(n -1)
- a(n) = 27×(1/3)^(n -1)
- a(n) = 6×(-4)^(n -1)
You can see that these formulas are exponential in nature.
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<u>Sum of Terms</u>
Another useful formula for geometric sequences is the formula for the sum of n terms.
S(n) = a(1)×(r^n -1)/(r -1) . . . . . sum of n terms of a geometric sequence
When |r| < 1, the sum converges as n approaches infinity. The infinite sum is ...
S = a(1)/(1-r)
Answer:
23,49,812
Step-by-step explanation:
Let's factorise it :
Using Distributive property we get :
⠀
Therefore,
Check the picture below.
since the second figure is also a square, then the sides touching the diagonals have to be all equal, and that'd only happen if those sides bisects the larger square's diagonal.