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natta225 [31]
3 years ago
11

In y=x+b,what is the slopeand how you know​

Mathematics
1 answer:
lys-0071 [83]3 years ago
3 0

Answer:

Y=kx+b

K is the slope

I'm smart

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A regulation baseball field measures 90 feet between each base. What is the distance around the bases in yards?
Naddika [18.5K]
Home to 1st base = 90 ft
1st base to 2nd base = 90 ft
2nd base to 3rd base = 90 ft
3rd base to home = 90 ft
so we have a total of : (90 * 4) = 360 ft

there are 3 ft in 1 yd....
so in 360 ft, there are : 360/3 = 120 yds <==

or u could just figure it between each base....90 ft = (90/3) = 30 yds per base...and u have 4 bases....so that (4 * 30) = 120 yds
4 0
3 years ago
Jenna has 8 pairs of jeans. Three of them are blue. What percentage of her jeans is blue?
Bond [772]
A) blue/total = (3+2)/(8+2) = 5/10 = 50%

b) blue/total = (3)/(8 +2) = 3/10 = 30%
5 0
3 years ago
What is the slope of the line on the graph?
maxonik [38]

Answer:

Slope = 1

Step-by-step explanation:

Rise over Run= 1/1

-I hope this helps have a great night

7 0
3 years ago
Under average driving conditions, the life lengths of automobile tires of a certain brand are found to follow an exponential dis
wariber [46]

Answer:

a) P(X>30000)=1-( 1- e^{-\frac{30000}{30000}})=e^{-1}=0.368

b) P(X>30000|X>15000)=P(X>15000)=1-( 1- e^{-\frac{15000}{30000}})=e^{-0.5}=0.607

Step-by-step explanation:

Previous concepts

The exponential distribution is "the probability distribution of the time between events in a Poisson process (a process in which events occur continuously and independently at a constant average rate). It is a particular case of the gamma distribution". The probability density function is given by:

P(X=x)=\lambda e^{-\lambda x}, x>0

And 0 for other case. Let X the random variable that represent "life lengths of automobile tires of a certain brand" and we know that the distribution is given by:

X \sim Exp(\lambda=\frac{1}{30000})

The cumulative distribution function is given by:

F(X) = 1- e^{-\frac{x}{\mu}}

Part a

We want to find this probability:

P(X>30000) and for this case we can use the cumulative distribution function to find it like this:

P(X>30000)=1-( 1- e^{-\frac{30000}{30000}})=e^{-1}=0.368

Part b

For this case w want to find this probability

P(X>30000|X>15000)

We have an important property on the exponential distribution called "Memoryless" property and says this:

P(X>a+t| X>t)=P(X>a)  

On this case if we use this property we have this:P(X>30000|X>15000)=P(X>15000+15000|X>15000)=P(X>15000)

We can use the definition of the density function and find this probability:

P(X>15000)=1-( 1- e^{-\frac{15000}{30000}})=e^{-0.5}=0.607

7 0
3 years ago
Please help I don't get this at all &gt;_&lt;
dangina [55]
Wow this... this is a lot YOU need help on
6 0
3 years ago
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