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natta225 [31]
3 years ago
11

In y=x+b,what is the slopeand how you know​

Mathematics
1 answer:
lys-0071 [83]3 years ago
3 0

Answer:

Y=kx+b

K is the slope

I'm smart

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11 5/9 + 10 1/3 plz help
Likurg_2 [28]
10 1/3= 31/3
31/3= 93/9

11 5/9= 104/9
93/9 + 104/9 = 197/9
197/9= 21 8/9



your answer is 21 & 8/9


Good Luck
XD
7 0
3 years ago
Write an expression that can be used to check the quotient of 646 ÷ 3
S_A_V [24]
3 times x equals to 646
3x=646

5 0
3 years ago
Read 2 more answers
PLSS HELP ME THE QUESTION AND EVERYTHING IS ABOVE what is the slope of the line and y intercept
AURORKA [14]

Answer:

C

Step-by-step explanation:

It is C. Have a great day!

6 0
3 years ago
Marjorie and Blaine make chairs together. Marjorie builds the seat and Blaine independently sews the cushions to rest on top of
Andrew [12]

Making 10 chairs would take Marjorie and Blaine<u> </u><u>21 hours and 40 minutes</u>.

<h3>How long does it take to make 10 chairs?</h3>

The total time it takes Marjorie and Blaine to perform their respective tasks in building a chair is multiplied by 10 chairs, respectively.  This time is known as their speed.

The resulting figures are summed to get the total time.

<h3>Data and Calculations:</h3>

The total time it takes Marjorie to build a chair is 15 hours (1.5 hours x 10)

The total time it takes Baline to sew cushions per chair is 400 minutes (40 x 10) or 6 hours and 40 minutes.

Therefore, the total time to build 10 chairs is 21 hours, 40 minutes (15 hours + 6 hours and 40 minutes).

Thus, making 10 chairs would take Marjorie and Blaine <u>21 hours and 40 minutes</u>.

Learn more about the time consumed at brainly.com/question/17146782

#SPJ1

8 0
2 years ago
1.) Find the length of the arc of the graph x^4 = y^6 from x = 1 to x = 8.
xxTIMURxx [149]

First, rewrite the equation so that <em>y</em> is a function of <em>x</em> :

x^4 = y^6 \implies \left(x^4\right)^{1/6} = \left(y^6\right)^{1/6} \implies x^{4/6} = y^{6/6} \implies y = x^{2/3}

(If you were to plot the actual curve, you would have both y=x^{2/3} and y=-x^{2/3}, but one curve is a reflection of the other, so the arc length for 1 ≤ <em>x</em> ≤ 8 would be the same on both curves. It doesn't matter which "half-curve" you choose to work with.)

The arc length is then given by the definite integral,

\displaystyle \int_1^8 \sqrt{1 + \left(\frac{\mathrm dy}{\mathrm dx}\right)^2}\,\mathrm dx

We have

y = x^{2/3} \implies \dfrac{\mathrm dy}{\mathrm dx} = \dfrac23x^{-1/3} \implies \left(\dfrac{\mathrm dy}{\mathrm dx}\right)^2 = \dfrac49x^{-2/3}

Then in the integral,

\displaystyle \int_1^8 \sqrt{1 + \frac49x^{-2/3}}\,\mathrm dx = \int_1^8 \sqrt{\frac49x^{-2/3}}\sqrt{\frac94x^{2/3}+1}\,\mathrm dx = \int_1^8 \frac23x^{-1/3} \sqrt{\frac94x^{2/3}+1}\,\mathrm dx

Substitute

u = \dfrac94x^{2/3}+1 \text{ and } \mathrm du = \dfrac{18}{12}x^{-1/3}\,\mathrm dx = \dfrac32x^{-1/3}\,\mathrm dx

This transforms the integral to

\displaystyle \frac49 \int_{13/4}^{10} \sqrt{u}\,\mathrm du

and computing it is trivial:

\displaystyle \frac49 \int_{13/4}^{10} u^{1/2} \,\mathrm du = \frac49\cdot\frac23 u^{3/2}\bigg|_{13/4}^{10} = \frac8{27} \left(10^{3/2} - \left(\frac{13}4\right)^{3/2}\right)

We can simplify this further to

\displaystyle \frac8{27} \left(10\sqrt{10} - \frac{13\sqrt{13}}8\right) = \boxed{\frac{80\sqrt{10}-13\sqrt{13}}{27}}

7 0
3 years ago
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