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Zina [86]
3 years ago
7

What is the factored form of 250x^3 − 16? A. 2(5x − 2)(25x2 + 10x + 4) B. 2(5x + 2)(25x2 − 10x + 4) C. (5x − 2)(25x2 + 10x + 4)

D. (5x + 2)(25x2 − 10x + 4)
Mathematics
1 answer:
Juli2301 [7.4K]3 years ago
5 0

Answer:

The choose A.

250 {x}^{3}  - 16 \\ 2(5x - 2)(25 {x}^{2}  + 10x + 4)

I hope I helped you^_^

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Which fraction is NOT equivalent to 4/9 ?
BARSIC [14]
Everything that is not 4/9
8 0
3 years ago
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Okay yes I know it's messy it was a long stressful day lol so just check the last two, are they written right? are they even rig
nata0808 [166]

Answer:

Yes

Step-by-step explanation:

Yes it is

No 1 is correct

No 2 is correct

No 3 is correct

No 4 is correct

and what i mean by correct is you answered it correct

I hope this helps you :)

6 0
3 years ago
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This is just for fun!
bixtya [17]
Addition or multiplication
add 2 or times 2
8 0
3 years ago
WZ and XR are diameters of circle C. The diagram is not drawn to scale. What is the measure of ZWX?
Inessa05 [86]

Answer:

Measure of arc ZWX is <u>230°.</u>

Step-by-step explanation:

Given:

arc WX = 50°

Now

The diameter divide a circle into two equal parts

so

arc\ ZWX=arc\ ZRW+arc\ WX

Since WZ is diameter of the circle.

arc\ ZRW=180\°

substituting in above equation we get

arc\ ZWX=180\°+50\°=230\°

Hence Measure of arc ZWX is <u>230°.</u>

7 0
3 years ago
Josie sold 790 tickets to a local car show for a total of $4,390.00. A ticket for a Child costs $4.00 and adult ticket costs $7.
Papessa [141]

Let's define the following variables first.

A = number of tickets sold for adults

C = number of tickets sold for children

From the question, we can say that or form the following equations:

1. A + C = 790 tickets

2. $7A + $4C = $4, 390

The first equation can also be written as A = 790 - C. We can use this equation and replace "A" in the second equation.

7(790-C)+4c=4,390

From that, we can solve "C" by solving the equation formed above.

\begin{gathered} \text{Distribute 7 to the terms inside the parenthesis.} \\ 7(790)-7(C)+4C=4,390 \\ 5,530-7C+4C=4,390 \\ \text{Subtract 5,530 on both sides of the equation.} \\ -7C+4C=-1140 \\ -3C=-1140 \\ \text{Divide -3 on both sides.} \\ C=380 \end{gathered}

Therefore, 380 tickets for children were sold.

Since there are 790 tickets in total that are sold and 380 tickets for children were sold, we can say that 410 tickets for adult was sold.

\begin{gathered} A=790-C \\ A=790-380 \\ A=410 \end{gathered}

3 0
1 year ago
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