lets work on the triangle with 60 and 70.
they make 130, and a triangle has 180 degrees, so that angle is 50
50+95+? is 180?
its 35
35+75 si 110, 180-110
so 70.
Try these solutions:
<u>Task 1.</u>
a) the required angle is arctan(CG/AC);
b) according to the condition CG=AE=11.4 (cm.);
c) BC=EH=9.6 (cm.), then
![AC=\sqrt{AB^2+BC^2}=\sqrt{18.4^2+9.6^2}=\sqrt{430.72} (cm.);](https://tex.z-dn.net/?f=AC%3D%5Csqrt%7BAB%5E2%2BBC%5E2%7D%3D%5Csqrt%7B18.4%5E2%2B9.6%5E2%7D%3D%5Csqrt%7B430.72%7D%20%28cm.%29%3B)
d) the required angle is:
![arctan\frac{CG}{AC}=arctan\frac{11.4}{\sqrt{430.72}}=arctan(0.549297)=28.5=29](https://tex.z-dn.net/?f=arctan%5Cfrac%7BCG%7D%7BAC%7D%3Darctan%5Cfrac%7B11.4%7D%7B%5Csqrt%7B430.72%7D%7D%3Darctan%280.549297%29%3D28.5%3D29)
Answer: 29°
<u>Task 2.</u>
a) the required angle is EFV (see the attached picture): arctan(EV/FE);
b) to calculate FE: FE=0.5AB=7.25 (cm.);
c) to calculate EV:
![EV=\sqrt{DV^2-DE^2} =\sqrt{17.2^2-(14.5/\sqrt{2})^2}=13.80996 (cm.);](https://tex.z-dn.net/?f=EV%3D%5Csqrt%7BDV%5E2-DE%5E2%7D%20%3D%5Csqrt%7B17.2%5E2-%2814.5%2F%5Csqrt%7B2%7D%29%5E2%7D%3D13.80996%20%28cm.%29%3B)
d) to calculate the required angle:
m(∠EFV)=arctan(13.80996/7.25)=arctan(1.9048)≈62.302°=62°.
Answer: 62°
2x+3=-7
-3=-7-3=-10
2x=-10
X=-5
Answer:
give more details
Step-by-step explanation: