1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
My name is Ann [436]
2 years ago
10

Evaluate the expression 5+3​

Mathematics
2 answers:
PolarNik [594]2 years ago
8 0

Answer:

8

Step-by-step explanation:

Serga [27]2 years ago
7 0

Answer:

8

Step-by-step explanation:

5 + 3 = 8

-Lexi

You might be interested in
Use stoke's theorem to evaluate∬m(∇×f)⋅ds where m is the hemisphere x^2+y^2+z^2=9, x≥0, with the normal in the direction of the
ludmilkaskok [199]
By Stokes' theorem,

\displaystyle\int_{\partial\mathcal M}\mathbf f\cdot\mathrm d\mathbf r=\iint_{\mathcal M}\nabla\times\mathbf f\cdot\mathrm d\mathbf S

where \mathcal C is the circular boundary of the hemisphere \mathcal M in the y-z plane. We can parameterize the boundary via the "standard" choice of polar coordinates, setting

\mathbf r(t)=\langle 0,3\cos t,3\sin t\rangle

where 0\le t\le2\pi. Then the line integral is

\displaystyle\int_{\mathcal C}\mathbf f\cdot\mathrm d\mathbf r=\int_{t=0}^{t=2\pi}\mathbf f(x(t),y(t),z(t))\cdot\dfrac{\mathrm d}{\mathrm dt}\langle x(t),y(t),z(t)\rangle\,\mathrm dt
=\displaystyle\int_0^{2\pi}\langle0,0,3\cos t\rangle\cdot\langle0,-3\sin t,3\cos t\rangle\,\mathrm dt=9\int_0^{2\pi}\cos^2t\,\mathrm dt=9\pi

We can check this result by evaluating the equivalent surface integral. We have

\nabla\times\mathbf f=\langle1,0,0\rangle

and we can parameterize \mathcal M by

\mathbf s(u,v)=\langle3\cos v,3\cos u\sin v,3\sin u\sin v\rangle

so that

\mathrm d\mathbf S=(\mathbf s_v\times\mathbf s_u)\,\mathrm du\,\mathrm dv=\langle9\cos v\sin v,9\cos u\sin^2v,9\sin u\sin^2v\rangle\,\mathrm du\,\mathrm dv

where 0\le v\le\dfrac\pi2 and 0\le u\le2\pi. Then,

\displaystyle\iint_{\mathcal M}\nabla\times\mathbf f\cdot\mathrm d\mathbf S=\int_{v=0}^{v=\pi/2}\int_{u=0}^{u=2\pi}9\cos v\sin v\,\mathrm du\,\mathrm dv=9\pi

as expected.
7 0
3 years ago
The radius of a cylinder is 3 cm and the height is 6 cm.
Ratling [72]

Answer

Step-by-step explanation:

A=2πrh+2πr2=2·π·3·6+2·π·32≈169.646

5 0
2 years ago
Read 2 more answers
What is the solution of the proportion? 6/a = 18/27
Marta_Voda [28]

Answer:

a=9

Step-by-step explanation:

To solve this proportion, we have to get the variable, a, by itself.

First, cross multiply.

6/a=18/27

Multiply the denominator of the first fraction by the numerator of the second, and the numerator of the second by the denominator of the first.

a*18=6*27

18a=162

Now, 18 and a are being multiplied. In order to get a by itself, perform the opposite of what is being done. They are being multiplied, so the opposite would be division. Divide both sides by 18.

18a/18=162/18

a=162/18

a=9

So, the proportion, with 9 substituted in for a, will be:

6/9=18/27

6 0
3 years ago
Read 2 more answers
Yeah help lol i don’t understand math
spayn [35]

Answer:

x=4.4

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
At Libby’s art and crafts, spoils of thread and 5 yards of fabric cost $22.33.
vazorg [7]
How are you supposed to solve this???
7 0
3 years ago
Other questions:
  • 1. What is the mean of the data set?
    13·2 answers
  • (X-2)(3x-4) help on this please show your work?
    8·2 answers
  • I need help with 25. 26. And 27 plz I don’t know how
    12·1 answer
  • John pays $15 per hour plus a fee of $10 to get his house cleaned.if he has to pay $160 how many hours did he get his house clea
    12·1 answer
  • 0.25×m = 3.6 m=_____.
    7·1 answer
  • Find 1/3 of 5 times 6
    11·1 answer
  • A pharmacy uses 4 x 10 to -3 liter of an ingredient in one dose of medication. The ingredient comes in a 2 liter bottle. How man
    6·1 answer
  • Ill brainlist anyone who anwsers this
    14·1 answer
  • PLEASE HELP I ONLY HAVE AN HOUR ​
    13·1 answer
  • -7x+6y=34 7x+4y=-24 helppp
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!