C. -5y -4 = -(x+3)^2 -1/2
Hope I am right.
X = -3.
The distance from p(-9, 0, 0) is
d = sqrt((x+9)^2 + y^2 + z^2)
The distance from q(3,0,0) is
d = sqrt((x-3)^2 + y^2 + z^2)
Let's set them equal to each other.
sqrt((x+9)^2 + y^2 + z^2) = sqrt((x-3)^2 + y^2 + z^2)
Square both sides, then simplify
(x+9)^2 + y^2 + z^2 = (x-3)^2 + y^2 + z^2
x^2 + 18x + 81 + y^2 + z^2 = x^2 - 6x + 9 + y^2 + z^2
18x + 81 = - 6x + 9
24x + 81 = 9
24x = -72
x = -3
So the desired equation is x = -3 which defines a plane.
Answer:
Step-by-step explanation:
l = 7 in
w = 11 in
h = 5 in
Surface area = 2*(lw +wh +hl)
= 2*(7*11 + 11*5 + 5*7)
= 2* (77+ 55 + 35)
= 2 * 167
= 334 square inches
We have an inequation:
x/3 < 3
⇒ x < 3*3
⇒ x < 9
The final answer is x < 9~
Answer:
Proof in explanation.
Step-by-step explanation:
I'm going to attempt this by squeeze theorem.
We know that 
is a variable number between -1 and 1 (inclusive).
This means that 
.
for all value 
. So if we multiply all sides of our inequality by this, it will not effect the direction of the inequalities.
By squeeze theorem, if
and 
, then we can also conclude that 
.
So we can actually evaluate the "if" limits pretty easily since both are continuous and exist at 
.
.
We can finally conclude that 
by squeeze theorem.
Some people call this sandwich theorem.
