Let the lengths of pregnancies be X
X follows normal distribution with mean 268 and standard deviation 15 days
z=(X-269)/15
a. P(X>308)
z=(308-269)/15=2.6
thus:
P(X>308)=P(z>2.6)
=1-0.995
=0.005
b] Given that if the length of pregnancy is in lowest is 44%, then the baby is premature. We need to find the length that separates the premature babies from those who are not premature.
P(X<x)=0.44
P(Z<z)=0.44
z=-0.15
thus the value of x will be found as follows:
-0.05=(x-269)/15
-0.05(15)=x-269
-0.75=x-269
x=-0.75+269
x=268.78
The length that separates premature babies from those who are not premature is 268.78 days
Answer:
1/9
Step-by-step explanation:
this is (-3)^(0-2) = (-3)^(-2) = 1 / 9.
Already in simplest form (0.562963)
Point slope formula is y= mx+b. To find the slope, or m, you need to find the "rise over run". rise = y coordinates, run = x coordinates. And the slope equation is y1-y2/x1-x2. So let's say the first point is (x1,y1) and the second is (x2,y2). that would be 35-(-31)/5-(-6)= 66/11 or 6/1 aka up six, across one. That is your slope. So far you have y=6x+b, next plug (5,35) into that equation and solve for b (aka the y intercept). So: 35=6(5)+b. 35-30=b, b=5. So your final equation is y=6x+5.
Answer:
I would say that the Answer is 35 I hope this isnt wrong..
