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podryga [215]
2 years ago
11

Pls help me to find out this answer e,f,g,h no. only​

Mathematics
2 answers:
nignag [31]2 years ago
7 0

Answer:

The picture is too blurry to make out!

Step-by-step explanation:

Hey! when you do problems like this it is very easy.

For multiplication: multiply the numbers and add the exponents.

For division: divide the numbers and subtract the exponents.

Arisa [49]2 years ago
5 0

Answer:

e answer is 3।

Step-by-step explanation:

9³ ÷ 3⁶

(3²)³ ÷ (3)⁶

3⁶‐⁶

3

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Can you help me with the rest of this worksheet (It’s due tomorrow)
vodomira [7]

Bro I think you should search algerba calcautor and then you'll get the answers

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3 years ago
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Solve for x , if x + 47 = -23 .<br><br> x =
love history [14]

Answer:

-70

Step-by-step explanation:

subtract 47 from both sides to get

x = -23 - 47

6 0
3 years ago
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Write the ordered pair for a point that is 9 units to the left of the origin and lies on the x-axis.
natulia [17]
(((((((((-9,0)))))))))
8 0
3 years ago
You measure 22 textbooks' weights, and find they have a mean weight of 64 ounces. Assume the population standard deviation is 5.
lara31 [8.8K]

Answer:

Step-by-step explanation:

We want to determine a 90% confidence interval for the true population mean textbook weight.

Number of sample, n = 22

Mean, u = 64 ounces

Standard deviation, s = 5.1 ounces

For a confidence level of 90%, the corresponding z value is 1.645. This is determined from the normal distribution table.

We will apply the formula

Confidence interval

= mean ± z ×standard deviation/√n

It becomes

64 ± 1.645 × 5.1/√22

= 64 ± 1.645 × 1.087

= 64 ± 1.788

The lower end of the confidence interval is 64 - 1.788 = 62.21 ounces

The upper end of the confidence interval is 64 + 1.788 = 65.79 ounces

Therefore, with 90% confidence interval, the true population mean textbook weight is between 62.21 ounces and 65.79 ounces

3 0
3 years ago
The maximum value of the function: f(x)= -5 x ^2 +30x-200 is?
VARVARA [1.3K]

Answer:

\displaystyle    - 155

Step-by-step explanation:

we are given a quadratic function

\displaystyle f(x) =  - 5 {x}^{2}  + 30x - 200

we want to figure out the minimum value of the function

to do so we need to figure out the minimum value of x in the case we can consider the following formula:

\displaystyle x _{ \rm  min} =  \frac{ - b}{2a}

the given function is in the standard form i.e

\displaystyle f(x) = a {x}^{2}  + bx + c

so we acquire:

  • b=30
  • a=-5

thus substitute:

\displaystyle x _{ \rm  min} =  \frac{ - 30}{2. - 5}

simplify multiplication:

\displaystyle x _{ \rm  min} =  \frac{ - 30}{ - 10}

simply division:

\displaystyle x _{ \rm  min} =  3

plug in the value of minimum x to the given function:

\displaystyle f (3)=  - 5 {(3)}^{2}  + 30.3 - 200

simplify square:

\displaystyle f (3)=  - 5 {(9)}^{}  + 30.3 - 200

simplify multiplication:

\displaystyle f (3)=  - 45  + 90- 200

simplify:

\displaystyle f (3)=   - 155

hence,

the minimum value of the function is -155

5 0
3 years ago
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