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ahrayia [7]
3 years ago
7

...I don’t understand umm can anyone help me smh-

Mathematics
1 answer:
Anna007 [38]3 years ago
3 0
Answer:

{Rounded to the nearest Hundredths place}

1) Mercury= 170.55
2) Venus= 277.86
3) Earth= 389.62
4) Mars= 401.29

Explanation:

Mercury: 3.3022 x 10^19= 170.549894825 which rounds to 170.55

Earth: 5.9722 x 10^24= 389.618945662 which rounds to 389.62

Venus: 4.8675 x 10^21= 277.855972801 which rounds to 277.86

Mars: 6.4185 x 10^23= 401.287714067 which rounds to 401.29

•So smallest to largest would be• 170.55, 277.86, 389.62, and 401.29

[I hope this helps][Sorry if it doesn’t make sense]

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C. \frac{1}{18}

Step-by-step explanation:

Given: Six cards numbered from 1 to 6 are placed in an empty bowl. First one card is drawn and then put back into the bowl then a second card is drawn.

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Sample space for sum of cards when two cards are drawn at random is \{(1,1),(1,2),(1,3)......(6,6)\}

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Sample space when sum of cards is 8 is \{(3,5),(5,3),(6,2),(2,6),(4,4)\}

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Sample space when one of the cards is 5 is \{(5,3),(3,5)\}

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Let A be the event that sum of cards is 8

p(\text{A}) =\frac{\text{total cases when sum of cards is 8}}{\text{all possible cases}}

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Let B be the event when one of the two cards is 5

probability than one of two cards is 5 when sum of cards is 8

p(\frac{\text{B}}{\text{A}})=\frac{\text{total case when one of the number is 5}}{\text{total case when sum is 8}}

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probability that sum of cards 8 is and one of cards is 5

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p(\text{A and B})=\frac{5}{36}\times\frac{2}{5}

p(\text{A and B})=\frac{1}{18}

if sum of cards is 8 then probability that one of the cards is 8 is \frac{1}{18}, option C is correct.

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