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svetoff [14.1K]

4 years ago

12

Adrianna is buying plants for her garden. She buys 15 flowering plants for $96. Pink flowering plants sell for $8, and purple fl

owering plants sell for $5. How many pink flowering plants did Adrianna buy?

2 answers:

Llana [10]4 years ago

7 0

Answer:

7

Step-by-step explanation:

edge

mrs_skeptik [129]4 years ago

5 0

7 5$ plants and 8 $8 plants

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Which system of linear inequalities is represented by the graph x+5y>5 y<2x+4

grandymaker [24]

Answer:

The lines represent the inequalities .

Further explanation:

The linear equation with slope m and intercept c is given as follows.

The formula for slope of line with points and can be expressed as,

Given:

The inequalities are as follows.

a. x – 5y < –5 and y < –2x – 4

b. x + 5y > 5 and y < 2x + 4

c. x – 5y < –5 and y < –2x + 4

d. x + 5y > 5 and y < 2x – 4

Step-by-step explanation:

The blue line intersects y-axis at , therefore the y-intercept is 4.

The blue line intersect the points that are and .

The slope of the line can be obtained as follows.

The slope of the line is m = 2.

Now check whether the inequality included origin or not.

Substitute in equation y=x+1.

0 is not greater than 1 which means that the inequality doesn’t include origin.

Therefore, the blue line is y < 2x + 4.

The orange line intersects y-axis at , therefore the y-intercept is 1.

The orange line intersect the points that are and .

The slope of the line can be obtained as follows.

The slope of the line is m = .

Now check whether the inequality included origin or not.

Substitute in equation y > .

0 is not greater than 1 which means that the inequality doesn’t include origin.

Therefore, the orange line is y > .

Solve the equation y > .

The equation of orange line is 5y + x > 5.

Option (a) is not correct as it satisfy the inequalities of the graph.

Option (b) is correct as it satisfy the inequalities of the graph.

Option (c) is not correct as it satisfy the inequalities of the graph.

Option (d) is is not correct as it satisfy the inequalities of the graph.

Hence, is correct.

7 0

3 years ago

Read 2 more answers

You can show your work if u want to<br> Find 2 numbers if Their sum is −7 and their difference is 14

Pepsi [2]

The larger number is (-7+14)/2 = 3.5.

The smaller number is (-7-14)/2 = -10.5.

_____

The two equations a+b=-7, a-b=14 can be solved to get these results. It is genrally convenient to solve them by adding one to the other, or subtracting one from the other.

7 0

3 years ago

I’ve been stuck can someone explain

MariettaO [177]

Answer:

Option (3)

Step-by-step explanation:

From the figure attached,

AB and CD are two chords intersecting at O.

m∠AOD = 37°

m∠AOC + m∠AOD = 180° [Since these angles are supplementary angles]

m∠AOC = 180° - 37°

= 143°

By the theorem of intersecting chords,

Measure of angle formed is the half of the sum of measures of the arcs intercepted by the angle and vertical angle.

m∠AOC = $\frac{1}{2}(\widehat{AC}+\widehat{BD})$

143° = $\frac{1}{2}[(x+5)+(x-5)]$

143° = x

Therefore, Option (3) will be the answer.

3 0

3 years ago

What is the mean (average) for -36, -25, 12, -4, 18?

Alina [70]

To find the mean add all the numbers up then divide by how many numbers you have.

-36+(-25)+12+(-4)+18= (-35)

there are a total of five numbers so divide by 5

(-35)/5=(-7)

answer -7

3 0

3 years ago

Read 2 more answers

The mean number of words per minute (WPM) read by sixth graders is 8888 with a standard deviation of 1414 WPM. If 137137 sixth g

Bingel [31]

Noticing that there is a pattern of repetition in the question (the numbers are repeated twice), we are assuming that the mean number of words per minute is 88, the standard deviation is of 14 WPM, as well as the number of sixth graders is 137, and that there is a need to estimate the probability that the sample mean would be greater than 89.87.

Answer:

"The probability that the sample mean would be greater than 89.87 WPM" is about $\\ P(z>1.56) = 0.0594$ .

Step-by-step explanation:

This is a problem of the <em>distribution of sample means</em>. Roughly speaking, we have the probability distribution of samples obtained from the same population. Each sample mean is an estimation of the population mean, and we know that this distribution behaves <em>normally</em> for samples sizes equal or greater than 30 $\\ n \geq 30$ . Mathematically

$\\ \overline{X} \sim N(\mu, \frac{\sigma}{\sqrt{n}})$ [1]

In words, the latter distribution has a mean that equals the population mean, and a standard deviation that also equals the population standard deviation divided by the square root of the sample size.

Moreover, we know that the variable Z follows a <em>normal standard distribution</em>, i.e., a normal distribution that has a population mean $\\ \mu = 0$ and a population standard deviation $\\ \sigma = 1$ .

$\\ Z = \frac{\overline{X} - \mu}{\frac{\sigma}{\sqrt{n}}}$ [2]

From the question, we know that

The population mean is $\\ \mu = 88$ WPM
The population standard deviation is $\\ \sigma = 14$ WPM

We also know the size of the sample for this case: $\\ n = 137$ sixth graders.

We need to estimate the probability that a sample mean being greater than $\\ \overline{X} = 89.87$ WPM in the <em>distribution of sample means</em>. We can use the formula [2] to find this question.

The probability that the sample mean would be greater than 89.87 WPM

$\\ Z = \frac{\overline{X} - \mu}{\frac{\sigma}{\sqrt{n}}}$

$\\ Z = \frac{89.87 - 88}{\frac{14}{\sqrt{137}}}$

$\\ Z = \frac{1.87}{\frac{14}{\sqrt{137}}}$

$\\ Z = 1.5634 \approx 1.56$

This is a <em>standardized value </em> and it tells us that the sample with mean 89.87 is 1.56<em> standard deviations</em> <em>above</em> the mean of the sampling distribution.

We can consult the probability of P(z<1.56) in any <em>cumulative</em> <em>standard normal table</em> available in Statistics books or on the Internet. Of course, this probability is the same that $\\ P(\overline{X} < 89.87)$ . Then

$\\ P(z$

However, we are looking for P(z>1.56), which is the <em>complement probability</em> of the previous probability. Therefore

$\\ P(z>1.56) = 1 - P(z$

$\\ P(z>1.56) = P(\overline{X}>89.87) = 0.0594$

Thus, "The probability that the sample mean would be greater than 89.87 WPM" is about $\\ P(z>1.56) = 0.0594$ .

5 0

3 years ago