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stich3 [128]
3 years ago
12

Identify the percentage, base, and rate: 14 is 70% of what number?​

Mathematics
2 answers:
liberstina [14]3 years ago
8 0

Answer:

9.8

Step-by-step explanation:

70*14/100

Ostrovityanka [42]3 years ago
5 0
Set up a proportion.

It should go 70/100 (which is 70%) and is/of

70/100 = 14/x

Notice “is” is next to 14. So 14 would go on top. X is the number we’re looking for. (Next to “of”)

Solve for x.

The answer is 20.

X = 20.
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1,868 to the nearest hundred
Citrus2011 [14]

Answer: 1,900

Step-by-step explanation:

You would round up to 1,900 because in the tens place is a 6 and when you have a number greater than or equal to 5 you round up. Hope this helps!

7 0
3 years ago
Need help with this problem
Zanzabum

Answer:

C. Priya needs to charge at least $21 per bracelet.

Step-by-step explanation:

117b - 505 \ge 1952

Add 505 to both sides.

117b \ge 2457

Divide both sides by 117.

b \ge 21

Answer: C. Priya needs to charge at least $21 per bracelet.

7 0
3 years ago
Kristin earns $6.50 for every hour she babysits for the Overstreet family. (Part A:) Last Friday, Kristin babysat for 4.5 hours.
bonufazy [111]

Answer:

The question seems not to be complete, below is a possible complete question:

Kristin earns $6.50 for every hour she babysits for the Overstreet family. Part A: Last Friday, Kristin babysat for 4.5 hours. How much money did she make during that job? $__________ Part B: Mrs. Overstreet has told Kristin that she will pay her $45.50 for tomorrow's babysitting job. How many hours will Kristin babysit then? __________ hours

Answers:

Part A: She makes $29.25

Part B: She babysat for 7 hours

Step-by-step explanation:

Part A:

amount earned per hour = $6.50

Number of hours worked = 4.5 hours

1 hour = $6.50

∴ 4.5 hours = 6.50 × 4.5 = $29.25

part B:

total amount to be earned = $45.50

earning rate = $6.50 per hour

\$6.50 = 1\ hour\\\$1 = \frac{1}{6.50}\ hour\\\therefore \$45.50 = 45.50 \times\frac{1}{6.50} \\= \frac{45.50}{6.50}\\ = 7\ hours

7 0
3 years ago
6 8<br> What is the determinant of K=<br> O -18<br> -8<br> O 10<br> O 18<br> ?
erik [133]

Answer:

A:-18

Step-by-step explanation:

Hopefully this helps!

3 0
3 years ago
An article presents a new method for timing traffic signals in heavily traveled intersections. The effectiveness of the new meth
Anna35 [415]

Answer:

With 89.9% we can say that the mean improvement is between 583.1 and 728.1 vehicles per hour.

Step-by-step explanation:

We are given that the effectiveness of the new method was evaluated in a simulation study. In 50 simulations, the mean improvement in traffic flow in a particular intersection was 655.6 vehicles per hour, with a standard deviation of 311.7 vehicles per hour.

A traffic engineer states that the mean improvement is between 583.1 and 728.1 vehicles per hour.

<em>Let </em>\bar X<em> = sample mean improvement</em>

The z-score probability distribution for sample mean is given by;

            Z =  \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } } ~ N(0,1)

where, \mu = mean improvement = 655.6 vehicles per hour

            \sigma = standard deviation = 311.7 vehicles per hour

            n = sample of simulations = 50

The Z-score measures how many standard deviations the measure is away from the mean. After finding the Z-score, we look at the z-score table and find the p-value (area) associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X.

Now, Probability that the mean improvement is between 583.1 and 728.1 vehicles per hour is given by = P(583.1 < \bar X < 728.1) = P(\bar X < 728.1) - P(\bar X \leq 583.1)

  P(\bar X < 728.1) = P( \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } } < \frac{728.1-655.6}{\frac{311.7}{\sqrt{50} } } ) = P(Z < 1.64) = 0.9495

  P(\bar X \leq 583.1) = P( \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } } \leq \frac{583.1-655.6}{\frac{311.7}{\sqrt{50} } } ) = P(Z \leq -1.64) = 1 - P(Z < 1.64)

                                                            = 1 - 0.9495 = 0.0505                      

<em />

<em>So, in the z table the P(Z </em>\leq<em> x) or P(Z < x) is given. So, the above probability is calculated by looking at the value of x = 1.64 in the z table which has an area of 0.9495.</em>

Therefore, P(583.1 < \bar X < 728.1) = 0.9495 - 0.0505 = 0.899 or 89.9%

Hence, with 89.9% we can say that the mean improvement is between 583.1 and 728.1 vehicles per hour.

6 0
3 years ago
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