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IgorLugansk [536]

3 years ago

8

What is the value of x? Please show the steps

1 answer:

nordsb [41]3 years ago

6 0

Let D be the endpoint of the angle bisector opposite A on lying on side BC. The angle bisector theorem states that the ratio of BD to CD is equal to the ratio of AB to AC. In this case, you have

$\dfrac{2x-1}{3x}=\dfrac9{15}$

(This is the same equation that you have, it's just rearranged.)

Multiply both sides by $3x$ and 15.

$15\times3x\times\dfrac{2x-1}{3x}=15\times3x\times\dfrac9{15}$
$15(2x-1)=3x\times9$

Now you can solve for $x$ .

$30x-15=27x$
$3x=15$
$x=5$

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Find the final amount for the investment given you initially have $5500 earning

stich3 [128]

Is the final value
P is the initial principle
r is the (annual) interest rate (as a decimal)
t is time (years)

10500%2Ae%5E%28%28.0625%2A25%29%29

5 0

3 years ago

What is the nth term of the sequence -2 -8 -18 -32 -50

andreev551 [17]

Answer:

-2n²

Step-by-step explanation:

Using the image attached:
We see that the second differences (blue ones) are all equal so we conclude that this is a quadratic sequence.
The quadratic sequence has the form:
$T_{n} = an^{2} +bn +c$

To find the value of a we just divide second difference ( -4 ) by 2:

$a = \frac{-4}{2}= -2$

Now we have:

$T_{n}= -2n^{2} +bn+c$

Substitute $n_{1}$ and $n_{2}$ into the equation above:

$T_{1} = -2(1)^{2} +b(1) +c$

$T_{2} = -2(2)^{2} +b(2)+c$

Since $T_{1}$ = -2 and $T_{2}$ = -8 , after simplification we have:

$b +c =0$
$2b+c=0$

The solution of this system is:

b=0, c =0

The general term is :

$T_{n} = -2n^{2}$

6 0

2 years ago

I need this answer ASAP

nexus9112 [7]

Answer:

216 cm²

Step-by-step explanation:

6*6=36

36*6=216

6 0

3 years ago

Read 2 more answers

The average (arithmetic mean) of y numbers is x. If 30 is added to the set of numbers, then the average will be x − 5. What is t

Alenkasestr [34]

Answer:

y = $\frac{1}{5}(x^{2}-35x)$

Step-by-step explanation:

Let the total numbers are n.

If the average of y numbers is x then we can form an equation

$\frac{y}{n}=x$

⇒ $\frac{n}{y}=\frac{1}{x}$

⇒ n = $\frac{y}{x}$ --------(1)

Now 30 is added to the set of numbers then average becomes (x - 5)

$\frac{y+30}{n+1}=(x-5)$

⇒ $\frac{(n+1)}{(y+30)}=\frac{1}{(x-5)}$

⇒ (n + 1) = $\frac{y+30}{x-5}$

⇒ n = $\frac{y+30}{x-5}$ - 1 ----- (2)

Now we equate the values of n from equation 1 and 2

$\frac{y}{x}$ = $\frac{y+30}{x-5}$ - 1

y(x - 5) = x(y + 30) - x(x - 5) [ By cross multiplication ]

xy - 5y = xy + 30x - x² + 5x

xy - xy - 5y = 35x - x²

-5y = 35x - x²

x² - 35x = 5y

y = $\frac{1}{5}(x^{2}-35x)$

6 0

3 years ago

Read 2 more answers

What is the value of x that makes the given equation true 9+8x-4-5x=-19

Elena L [17]

Answer:

x = -8

Step-by-step explanation:

9+8x-4-5x=-19

5+8x-5x=-19

5+3x=-19

-5 =-19

3x = -24

3/3 = -24/3

x= -8

8 0

2 years ago