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liq [111]
3 years ago
5

M∠DEF = __because they are_________

Mathematics
1 answer:
vovikov84 [41]3 years ago
3 0

Answer:

m∠GDE

alternate interior angles

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A cube has six sides that are numbered 1 to 6 the sides numbered 1, 3 and 5 are yellow and the sides numbered 2, 4 and 6 are ora
natita [175]

Answer:

0/0

Step-by-step explanation:

The number can't be even and yellow if all yellow numbers are odd.

3 0
3 years ago
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12. What is the value of x?
lutik1710 [3]

Answer:

68 degrees

Step-by-step explanation:

180-44= 136

136/2= 68

since both sides are equal in length

4 0
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The Bishop family celebrated a birthday by dining out at a local restaurant. Their
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-1,-4,-7,-10 write an equation to find the nth term of each sequence. Then find a24
Natasha_Volkova [10]

Answer:

\boxed {a_{24} = - 70}

Step-by-step explanation:

According to the following pattern sequence (-1, -4, -7, -10 ), it is <u>Arithmetic Sequence</u>, because every negative number is subtracted by 3. So, to find the <u>24th term</u>, you need to use the <u>Arithmetic Sequence Formula</u> and solve to find the 24th term:

a_{n} = a_{1} +  (n - 1) d

a_{n}: nth term in the sequence

a_{1}: 1st term

n: term position

d: Common difference

-Apply to the formula:

a_{24} = -1 - 3 (24 - 1)

a_{n} = a_{24}

a_{1} = -1

n = 24

d = -3

-Solve:

a_{24} = -1 - 3 (24 - 1)

a_{24} = -1 - 3 (23)

a_{24} = -1 - 69

\boxed {a_{24} = - 70}

Therefore, the 24th term is -70.

8 0
3 years ago
What are the answers to these 2 question 4&amp;5 PLZ HELP
Ahat [919]
The first problem:

y = -2 x²  ⇒⇒⇒ x² = -y/2 →(1)33 x² + y² = 27 → (2)
By substitution from (1) at (2) with the value of x²
∴ 33 (-y/2) + y² = 27
∴ y² - 16.5 y - 27 = 0
a = 1 , b = -16.5 , c = -27
∴ y= \frac{-b \pm  \sqrt{b^2-4ac} }{2a} = \frac{16.5 \pm  \sqrt{(-16.5)^2-4*1*(-27)} }{2*1}
∴ y = 18 or y = -3/2
By substitution from at (1) with the value of y
for y = 18   ⇒⇒⇒ x² = -18/2 = -9 (unacceptable)
for y = -3/2 ⇒⇒⇒ x² = -(-3/2)/2 = 3/4
∴ x= \pm \sqrt{ \frac{3}{4} } = \pm  \frac{ \sqrt{3} }{2} &#10;
The correct options are 2 , 7
Solution of the system of equations is 
( \frac{ \sqrt{3} }{2} ,  \frac{-3}{2} )
and   
( -\frac{\sqrt{3} }{2} ,  \frac{-3}{2} )
==================================
The second problem:
The general equation of the hyperbole is 
\frac{x^2}{a^2} - \frac{y^2}{b^2} =1&#10;&#10;Transverse axis is horizontal &#10;&#10;The equation if the asymptotes are y = \pm \frac{b}{a}x
For the given equation:
\frac{x^2}{225} -  \frac{y^2}{36} = 1
a² = 225 ⇒⇒⇒ a = √225 = 15
b² = 36   ⇒⇒⇒ b = √36 = 6
∴ the slope of the <span><span>asymptotes = </span>b/a   and  -b/a
</span><span>
</span><span>b/a = 6/15 = 2/5
</span><span>
</span><span>-b/a = -6/15 = -2/5
</span><span>
</span><span>∴ m = 2/5   and   m = -2/5
</span>






3 0
3 years ago
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