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Neporo4naja [7]

3 years ago

7

A female executive selecting her wardrobe purchased five blazers, three blouses, and five skirts in coordinating colors. How man

y ensembles consisting of a blazer, a blouse, and a skirt can she create from this collection?

1 answer:

Viktor [21]3 years ago

8 0

She can create a total of 75 ensembles

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Find the sum of -2x+5x-7 and -3x-4x-6

scoray [572]

Answer:

-4x-13

Step-by-step explanation:

To figure out the sum, you have to add like terms.

This is how it would look like:

$-2x + 5x - 3x - 4x -7 - 6\\=3x - 3x - 4x - 13\\= -4x - 13$

8 0

3 years ago

Barry bought 21 stamps from a hobby shop. he gave 3/7 of them to his sister, how many stamps did he have left?

Alex17521 [72]

He gave away 9 (20 x (3/7) =9) so 21-9=12

7 0

3 years ago

Maggie graphed the image of a 90 counterclockwise rotation about vertex A of . Coordinates B and C of are (2, 6) and (4, 3) and

Lemur [1.5K]

Answer:

A(2,2)

Step-by-step explanation:

Let the vertex A has coordinates $(x_A,y_A)$

Vectors AB and AB' are perpendicular, then

$\overrightarrow {AB}=(2-x_A,6-y_A)\\ \\\overrightarrow {AB'}=(-2-x_A,2-y_A)\\ \\\overrightarrow {AB}\perp\overrightarrow {AB'}\Rightarrow \overrightarrow {AB}\cdot \overrightarrow {AB'}=0\Rightarrow (2-x_A)(-2-x_A)+(6-y_A)(2-y_A)=0$

Vectors AC and AC' are perpendicular, then

$\overrightarrow {AC}=(4-x_A,3-y_A)\\ \\\overrightarrow {AC'}=(1-x_A,4-y_A)\\ \\\overrightarrow {AC}\perp\overrightarrow {AC'}\Rightarrow \overrightarrow {AC}\cdot \overrightarrow {AC'}=0\Rightarrow (4-x_A)(1-x_A)+(3-y_A)(4-y_A)=0$

Now, solve the system of two equations:

$\left\{\begin{array}{l}(2-x_A)(-2-x_A)+(6-y_A)(2-y_A)=0\\ \\(4-x_A)(1-x_A)+(3-y_A)(4-y_A)=0\end{array}\right.\\ \\\left\{\begin{array}{l}-4-2x_A+2x_A+x_A^2+12-6y_A-2y_A+y^2_A=0\\ \\4-4x_A-x_A+x_A^2+12-3y_A-4y_A+y_A^2=0\end{array}\right.\\ \\\left\{\begin{array}{l}x_A^2+y_A^2-8y_A+8=0\\ \\x_A^2+y_A^2-5x_A-7y_A+16=0\end{array}\right.$

Subtract these two equations:

$5x_A-y_A-8=0\Rightarrow y_A=5x_A-8$

Substitute it into the first equation:

$x_A^2+(5x_A-8)^2-8(5x_A-8)+8=0\\ \\x_A^2+25x_A^2-80x_A+64-40x_A+64+8=0\\ \\26x_A^2-120x_A+136=0\\ \\13x_A^2-60x_A+68=0\\ \\D=(-60)^2-4\cdot 13\cdot 68=3600-3536=64\\ \\x_{A_{1,2}}=\dfrac{60\pm8}{2\cdot 13}=\dfrac{34}{13},2$

Then

$y_{A_{1,2}}=5\cdot \dfrac{34}{13}-8 \text{ or } 5\cdot 2-8\\ \\=\dfrac{66}{13}\text{ or } 2$

Rotation by 90° counterclockwise about A(2,2) gives image points B' and C' (see attached diagram)

8 0

3 years ago

HELP ME ASAP PLEASE I'LL GIVE U BRAINIEST Recall your studies of geometry (or another math course) and algebra. Choose one that

guajiro [1.7K]

This is what I put in my response

For me I thought that algebra was better. I loved algebra I mean math is math somethings in math are hard, somethings are easy, sometimes in math you will come across something that seems impossible. Sometimes you will fly thru but, what makes the journey bearable is the people around you. Why I think algebra is better is because of the people that were in math course with me and my teacher because. The teachers make all the difference.

4 0

3 years ago

Find the measure of the indicated angle to the nearest degree

Alisiya [41]

Answer:

The answer to your question is below

Step-by-step explanation:

14) sin Ф = 32/33

sin Ф = 0.9697

Ф = 75.86°

15) sin Ф = 16/36

sin Ф = 0.444

Ф = 26.39°

16) sin Ф = 29/36

sin Ф = 0.806

Ф = 53.66°

17) cos Ф = 11/34

cos Ф = 0.324

Ф = 71.12°

18) sin Ф = 21/40

sin Ф = 0.525

Ф = 31.67°

19) cos Ф = 6/14

cos Ф = 0.429

Ф = 64.62°

20) cos Ф = 38/39

cos Ф = 0.974

Ф = 13°

3 0

3 years ago