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wel
2 years ago
8

The Spanish club began the year with $15.00 in its account. At the end of their candy sale fundraiser,the club had 654.75.How mu

ch money did the club make?
Mathematics
1 answer:
Anit [1.1K]2 years ago
3 0
Step 1: 654.75-15.00= $639.75
Therefore the club made $639.75
You might be interested in
-3.75+2(-4x+6.1)-3.25
Pani-rosa [81]

The value of x is 0.65

<u>Step-by-step explanation:</u>

This solution is given by solving the given problem using BODMAS rule.

This means that the steps to be followed to find the solution should be in the order of BODMAS rule.

B- Bracket, O- of, D- Division, M- Multiplication, A- Addition, S- Subtraction.

This rule states that the 1st operation must be done for Brackets.

⇒ -3.75+2(-4x+6.1)-3.25 = 0

⇒ -3.75 -8x + 12.2 -3.25 = 0

The addition operation should be performed next and then followed by subtraction.

⇒ -8x -7+ 12.2 = 0

<u>To find the value of x :</u>

Keeping the x term alone on one side and moving the constants on other side,

⇒ -8x = -12.2 + 7

⇒ -8x = -5.2

⇒ x = 5.2/8

⇒ x = 0.65

3 0
2 years ago
A sample of 1500 computer chips revealed that 32% of the chips do not fail in the first 1000 hours of their use. The company's p
Grace [21]

Answer:

Yes, we have sufficient evidence at the 0.02 level to support the company's claim.

Step-by-step explanation:

We are given that a sample of 1500 computer chips revealed that 32% of the chips do not fail in the first 1000 hours of their use. The company's promotional literature claimed that above 29% do not fail in the first 1000 hours of their use.

Let Null Hypothesis, H_0 : p \leq 0.29  {means that less than or equal to 29% do not fail in the first 1000 hours of their use}

Alternate Hypothesis, H_1 : p > 0.29  {means that more than 29% do not fail in the first 1000 hours of their use}

The test statics that will be used here is One-sample proportions test;

          T.S. = \frac{\hat p -p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }  ~ N(0,1)

where, \hat p = proportion of chips that do not fail in the first 1000 hours of their use = 32%

            n = sample of chips = 1500

So, <u>test statistics</u> = \frac{0.32-0.29}{\sqrt{\frac{0.32(1-0.32)}{1500} } }

                              = 2.491

<em>Now, at 0.02 level of significance the z table gives critical value of 2.054. Since our test statistics is more than the critical value of z so we have sufficient evidence to reject null hypothesis as it fall in the rejection region.</em>

Therefore, we conclude that more than 29% do not fail in the first 1000 hours of their use which means we have sufficient evidence at the 0.02 level to support the company's claim.

7 0
3 years ago
Please answer as soon as possible
OlgaM077 [116]

Answer:

  • 30 cubic units³

Step-by-step explanation:

<u>Given equation:</u>

  • 3 * 2 * 5

<u>Solve for cubic units³</u>

  • 3 * 2 * 5
  • = 6 * 5
  • = 30

There are 30 cubic inches³.

<u>Word form:</u>

  • Three times Two Times Five
  • equals Six times Five
  • equals Thirty.

There are Thirty cubic inches³.

7 0
1 year ago
Read 2 more answers
Mr.Marquez had 123 eggs in his refrigerator in his restaurant.He put 32 more cartoons of eggs in the refrigerator.Each cartoon c
skad [1K]

Answer:

2790

Step-by-step explanation:

3 0
2 years ago
Read 2 more answers
Can someone plz help me solve this..
Vika [28.1K]

Answer:sorry I'm a 4 grader

Step-by-step explanation:

7 0
2 years ago
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