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zalisa [80]
3 years ago
5

The measures of the angles of △ABC are given by the expressions in the table.

Mathematics
1 answer:
alexgriva [62]3 years ago
7 0
M<A= 115
m<B=50
i am sure of the answer
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John and Beth plan to visit a bookstore. Based on their previous visits to this bookstore, the probability distributions for the
lora16 [44]

Answer:

D) 0.1250

Step-by-step explanation:

Let P(J) = Probability of John to purchase 0 books

Let P(B) = Probability of Beth to purchase 0 books

P(J∩B) = Probability that both john and Beth will purchase 0 books .ie. a total of 0 books is purchased.

Since the decisions to purchase books are two independents events,

P(J∩B) = P(J) * P(B)

P(J) = 0.5

P(B) = 0.25

P(J∩B) = 0.5 * 0.25

P(J∩B) = 0.125

8 0
3 years ago
What are the domain and range for each of the following functions​
coldgirl [10]

Answer:

a.) DomainL: -2 ≥ x < 1        Range:   1 ≥ y < 2

b.) DomainL: -2 > x < 2        Range:   -2 > y < 2

Step-by-step explanation:

look up what the open and closed dots mean

understand how to determine values on the y or x axis

7 0
3 years ago
ROSSEL
malfutka [58]

Answer:

√41

Step-by-step explanation:

4^2+5^2

16+25=41

√41

8 0
4 years ago
Read 2 more answers
Part of the area under this ramp serves for storage. Items can be stored only in the unshaded part of the ramp
Mekhanik [1.2K]

Answer:

48.1 m³ available, 2.5m³ not available

Step-by-step explanation:

Tan(X) = 4.5/(5.8+1.7)

Tan X = 3/5

Hypotenuse² = 3² + 5² = 34

Sin X = 3/sqrt(34)

X = 30.96

1/sinX = 1.7/SinY

Y = 61.003°

Third angle: 180 - X - Y = 88.037

Volume

= ½ × 1.7 × 1 × sin(88.038) × 3

= .

= 2.548

= 2.5m³

Available for storage:

½×4.5×7.5×3 - 2.548

= 48.077 = 48.1 m³

7 0
3 years ago
Make a box and whiskers plot of the data. average temperature in Pittsburgh in June 79,70,73,84,83,88,75,72,76,68,68,79,84,74,75
aliya0001 [1]
The box-and-whisker plot is attached.

We first order the data from least to greatest:
67,68,68,69,70,72,73,74,75,75,76,78,79,79,80,83,84,85,85,88

Now we find the median.  Since there are 20 data values, the median is between 75 and 76:
(75+76)/2 = 151/2 = 75.5

Now we find the Lower Quartile (LQ).  We do this by finding the median of the lower half of data (from the median down).  There are 10 values here; the median is between 70 and 72:
(70+72)/2 = 142/2 = 71

Find the Upper Quartile (UQ).  Do this by finding the median of the upper half of data (from the median up).  There are 10 values here; the median is between 80 and 83:
(80+83)/2 = 163/2 = 81.5

The middle bar of the box is over the median.  The left hand side of the box is over LQ, and the right hand side of the box is over UQ.  Now we draw a whisker from the box to the highest value, 88, and from the box to the lowest value, 67.

7 0
3 years ago
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