At the end of the zeroth year, the population is 200.
At the end of the first year, the population is 200(0.96)¹
At the end of the second year, the population is 200(0.96)²
We can generalise this to become at the end of the nth year as 200(0.96)ⁿ
Now, we need to know when the population will be less than 170.
So, 170 ≤ 200(0.96)ⁿ
170/200 ≤ 0.96ⁿ
17/20 ≤ 0.96ⁿ
Let 17/20 = 0.96ⁿ, first.
log_0.96(17/2) = n
n = ln(17/20)/ln(0.96)
n will be the 4th year, as after the third year, the population reaches ≈176
Answer:
brainliest answer
Step-by-step explanation:
7 and 2
7+2=9
7-2=5
Well you would take the store credit and subtract that from the total so you would do 52.22-39.58 and you would have to spend $12.64
The shape consists of 5 faces. One on the front, one on the back, one on the left of the shape, the other on the right, and of course the one on the bottom :)
Hope it helped.
