Set up a table.
Pages | Minutes
-----------------------
25. | 30
? | 200
One way is to cross multipy.
200 x 25 = 5,000
30 x ? = 5,000
So do 5,000 divided by 30 and you get your answer
The entire yard is 36x54 so you would draw a rectangle with those measurements, since there is a border of 3 you should draw another rectangle in the middle with measurements 6 less than the original. 30x48
since you are finding the area of the walk, you would find the larger area, then subtract the smaller rectangle
(36*54)-(30*48)
1944-1440
504 square feet of walk
Answer:
{x| -2 ≤ x < 5}
Step-by-step explanation:
The domain is the x value in a graph, function e.t.c. From the farthest point to the left of the x-axis, we see -2. And from the farthest point to the right of the x-axis, we see 5. Therefore, the domain is {x| -2 ≤ x < 5}, Option C
Look here for visuals:
Complete question :
Suppose that of the 300 seniors who graduated from Schwarzchild High School last spring, some have jobs, some are attending college, and some are doing both. The following Venn diagram shows the number of graduates in each category. What is the probability that a randomly selected graduate has a job if he or she is attending college? Give your answer as a decimal precise to two decimal places.
What is the probability that a randomly selected graduate attends college if he or she has a job? Give your answer as a decimal precise to two decimal places.
Answer:
0.56 ; 0.60
Step-by-step explanation:
From The attached Venn diagram :
C = attend college ; J = has a job
P(C) = (35+45)/300 = 80/300 = 8/30
P(J) = (30+45)/300 = 75/300 = 0.25
P(C n J) = 45 /300 = 0.15
1.)
P(J | C) = P(C n J) / P(C)
P(J | C) = 0.15 / (8/30)
P(J | C) = 0.5625 = 0.56
2.)
P(C | J) = P(C n J) / P(J)
P(C | J) = 0.15 / (0.25)
P(C | J) = 0.6 = 0.60