Find the product of 3-4i and its conjugate.
1 answer:
Remember that i²=-1
the conjugate of a+bi is a-bi
so
3-4i
the conjugate is 3+4i
product
(3-4i)(3+4i)
hey, this looks familiar
remember (a-b)(a+b)=a²-b²
so
(3-4i)(3+4i)=(3)²-(4i)²=9-(16i²)=9-16(-1)=9+16=25
the product is 25
it's conjugate is 3+4i
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