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adell [148]
2 years ago
6

Find the measure of the (3y)° angle. *

Mathematics
1 answer:
Zigmanuir [339]2 years ago
6 0

Answer:

35+(y-15)+3y=180

35+y-15+3y=180

35-15+y+3y=180

20+4y=180

4y=160

y=40

3y=120

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The standard form of the equation for a quadratic function is, with he vertex of the graph of the function at the point (p,q). t
ludmilkaskok [199]

Answer:

p = ½ (x₁ + x₂)

q = a (x₁x₂ − ¼ (x₁ + x₂)²)

Step-by-step explanation:

y = a (x − x₁) (x − x₂)

Expand:

y = a (x² − x₁x − x₂x + x₁x₂)

y = a (x² − (x₁ + x₂)x + x₁x₂)

Distribute a to the first two terms:

y = a (x² − (x₁ + x₂)x) + ax₁x₂

Complete the square:

y = a (x² − (x₁ + x₂)x + ¼(x₁ + x₂)²) + ax₁x₂ − ¼ a(x₁ + x₂)²

y = a (x − ½ (x₁ + x₂))² + a (x₁x₂ − ¼ (x₁ + x₂)²)

Therefore:

p = ½ (x₁ + x₂)

q = a (x₁x₂ − ¼ (x₁ + x₂)²)

3 0
2 years ago
Find sin θ if θ is in Quadrant III and tan θ = . 0.958
Leokris [45]
Use the following identities:
sec^2 = 1  + tan^2 \\  \\ sec = \frac{1}{cos} \\  \\ sin^2 = 1 - cos^2
Also because the angle is in quadrant 3, sin must be negative.
Therefore
sin = - \sqrt{1 - \frac{1}{1 + tan^2}}
Subbing in tan = 0.958
sin \theta = -0.69178
7 0
2 years ago
Evaluate \dfrac{e}{4}+2f-3 4e +2f−3 when e=12e=12 and f=\dfrac12f= 21<br> ​
dusya [7]

Answer:

\frac{13+\left(-3\right)^2+4\left(-3\right)+1-\left(-10-\left(-6\right)\right)}{\frac{\left(4+5\right)}{\left(4^2-3^2\left(4-3\right)-8\right)}+12}=5


Step-by-step explanation:


7 0
3 years ago
What is the value of the expression?<br> 1/3-5/6<br> Enter your answer in simplest form.
algol [13]

Answer:

(1/3 - 5/6) / 5/6

You want to make 1/3 and 5/6 have the same denominator so you multiply both the numerator and denominator of 1/3 by 2 to get 2/6. You plug that back into your equation to get: (2/6 - 5/6) / 5/6. 2/6 - 5/6 is -3/6. -3/6 divided by 5/6 is -3/6 multiplied by 6/5 which is -3/5. 

5 0
3 years ago
Read 2 more answers
What is the frequency of the sinusoidal graph ?
disa [49]

Answer:

The frequency of the given sinusoidal graph is 4.

Step-by-step explanation:

The frequency of a sinusoidal graph is the number of cycles it completes in the interval 0 to 2π radians.

From the given sinusoidal graph it is noticed that the the graph complete its one cycle in the interval 0 to \frac{\pi}{2}.

If the complete its one cycle in \frac{\pi}{2}, then the number of cycles completed by the graph in the inteval 0 to 2π is

\frac{\pi}{2}\times frequency=2\pi

frequency=2\pi \times \frac{2}{\pi}

frequency=4

Therefore the frequency of the given sinusoidal graph is 4.

7 0
3 years ago
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