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2 years ago

True or False? Set A = { X | X is an even whole number between 0 and 2} = ∅

Mathematics

2 answers:

N76 [4]2 years ago

7 0

It is false because 0and 2 and the middle number will be 1

Rufina [12.5K]2 years ago

5 0

Here are examples of "even whole numbers:" 2, 4, 8, 12, 16, ...

X must be a whole number. The only whole number between 0 and 2 is 1. Unfortunately, that's not an even number. Thus, Set A is "empty." The given statement is FALSE.

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Name the subsets of which the number 13 belongs to. If you can even just tell me how to find the subset that's great! :)

Mamont248 [21]

It also belongs to set of natural numbers.

6 0

2 years ago

What is the distance rounded to the nearest tenth between the points (2 -2) and (6 3)

kotegsom [21]

Answer:

The distance between the points is approximately 6.4

Step-by-step explanation:

The given coordinates of the points are;

(2, -2), and (6, 3)

The distance between two points, 'A', and 'B', on the coordinate plane given their coordinates, (x₁, y₁), and (x₂, y₂) can be found using following formula;

$l = \sqrt{\left (y_{2}-y_{1} \right )^{2}+\left (x_{2}-x_{1} \right )^{2}}$

Substituting the known 'x', and 'y', values for the coordinates of the points, we have;

$l_{(2, \, -2), \ (6, \, 3) } = \sqrt{\left (3-(-2) \right )^{2}+\left (6-2 \right )^{2}} = \sqrt{5^2 + 4^2} = \sqrt{41}$

Therefore, the distance between the points, (2, -2), and (6, 3) = √(41) ≈ 6.4.

4 0

2 years ago

Help help math math math

Anarel [89]

Answer:

i think this is right i hope it helped :)

Step-by-step explanation:

5m - 8 = 2m + 1

5m + 2m - 8 = 1

7m - 8 = 1

7m = 7

m = 1

6 0

1 year ago

Read 2 more answers

The following data gives the speeds (in mph), as measured by radar, of 10 cars traveling north on I-15. 76 72 80 68 76 74 71 78

____ [38]

Answer:

71.123 mph ≤ μ ≤ 77.277 mph

Step-by-step explanation:

Taking into account that the speed of all cars traveling on this highway have a normal distribution and we can only know the mean and the standard deviation of the sample, the confidence interval for the mean is calculated as:

$m-t_{a/2,n-1}\frac{s}{\sqrt{n} }$ ≤ μ ≤ $m+t_{a/2,n-1}\frac{s}{\sqrt{n} }$

Where m is the mean of the sample, s is the standard deviation of the sample, n is the size of the sample, μ is the mean speed of all cars, and $t_{a/2,n-1}$ is the number for t-student distribution where a/2 is the amount of area in one tail and n-1 are the degrees of freedom.

the mean and the standard deviation of the sample are equal to 74.2 and 5.3083 respectively, the size of the sample is 10, the distribution t- student has 9 degrees of freedom and the value of a is 10%.

So, if we replace m by 74.2, s by 5.3083, n by 10 and $t_{0.05,9}$ by 1.8331, we get that the 90% confidence interval for the mean speed is: