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kiruha [24]
2 years ago
11

Solve for x. Please look at the picture and answer it. Thank you.

Mathematics
1 answer:
AleksAgata [21]2 years ago
8 0

45+63+(4x-12)= 180°

96+4x = 180°

4x=84

x = 21

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Express as a single power of 2
den301095 [7]
When you multiply powers, they add, and when you divide them they subtract.
So I would first add the 2^a + 2^b +2^c to get 2^(a+b+c)
Then, divide by 2^(a+b). Because when you divide powers they subtract, you will be taking away the (a+b) from the (a+b+c) and you will be left with c on its own.
The answer is 2^c
6 0
3 years ago
Determine whether the following problem involves a permutation or combination.​ (It is not necessary to solve the​ problem.) How
Aleksandr [31]

Answer:

Permutation

Step-by-step explanation:

Since we are talking about passwords the order of the letters matters, i.e, the pasword UpT is different to the pasword pUT. Therefore, the problem involves all the permutations of 33 letters, from the given letters, where no repetitions of letters are allowed.

4 0
3 years ago
SUPER EASY FOR POINTS!!!!solve: x-3=3x-2
Savatey [412]

Answer:

Polynomial equation solver

x-3=3x-2

Standard form:

−2x − 1 = 0

Factorization:

−(2x + 1) = 0

Solutions:

x = −1

2

= -0.5

3 0
3 years ago
Yahoo creates a test to classify emails as spam or not spam based on the contained words. This test accurately identifies spam (
Amiraneli [1.4K]

Answer and Step-by-step explanation:

The computation is shown below:

Let us assume that

Spam Email be S

And, test spam positive be T

Given that

P(S) = 0.3

P(\frac{T}{S}) = 0.95

P(\frac{T}{S^c}) = 0.05

Now based on the above information, the probabilities are as follows

i. P(Spam Email) is

= P(S)

= 0.3

P(S^c) =  1 - P(S)

= 1 - 0.3

= 0.7

ii. P(\frac{S}{T}) = \frac{P(S\cap\ T}{P(T)}

= \frac{P(\frac{T}{S}) . P(S) }{P(\frac{T}{S}) . P(S) + P(\frac{T}{S^c}) . P(S^c) }

= \frac{0.95 \times 0.3}{0.95 \times 0.3 + 0.05 \times 0.7}

= 0.8906

iii. P(\frac{S}{T^c}) = \frac{P(S\cap\ T^c}{P(T^c)}

= \frac{P(\frac{T^c}{S}) . P(S) }{P(\frac{T^c}{S}) . P(S) + P(\frac{T^c}{S^c}) . P(S^c) }

= \frac{(1 - 0.95)\times 0.3}{ (1 -0.95)0.95 \times 0.3 + (1 - 0.05) \times 0.7}

= 0.0221

We simply applied the above formulas so that the each part could come

8 0
3 years ago
Line parallel to y=-3x 4 and goes through (-4,6)
Eduardwww [97]
Y=-3x+4
Gradient, m= -3
Parallel lines have equal gradients;
So, equation II,
y=mx+c
y=-3x+c
Replacing for x and y using point (-4, 6)
6=-3(-4)+c
6=12+c
6-12=c
c=-6
y=-3x-6
7 0
3 years ago
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