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3 years ago

15

a family uses 1303 kWh of electric energy in a month. if the power company charges $0.08 cents per kilowatt, what is the total e

lectric bill for the month?

1 answer:

marshall27 [118]3 years ago

3 0

$104.25 is the electric bill for the month

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8(2+1) - 4+22 help with this plz

olga_2 [115]

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Distribute the parentheses, then add like terms

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3 years ago

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Find the height of a triangle in which base is 25cm and<br> area is 200cm2.

Arisa [49]

Answer:

16

Step-by-step explanation:

(200*2)/25=16

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3 years ago

How do you find the square root of a whole number which are not perfect square

Gre4nikov [31]

Answer: Finding the square root of numbers that aren't perfect squares

Divide: Divide the number that you are finding the squared root for with the number you picked in step 1. Average: Take the average of the number you got in step 2 and the square root. Repeat: Repeat steps 2 and 3 until the number is accurate enough for you.

Step-by-step explanation:

BRAINLESS PLEASE

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3 years ago

Find the derivative.

krek1111 [17]

Answer:

$\displaystyle f'(x) = \bigg( \frac{1}{2\sqrt{x}} - \sqrt{x} \bigg)e^\big{-x}$

General Formulas and Concepts:

<u>Algebra I</u>

Terms/Coefficients

Expanding/Factoring

<u>Calculus</u>

Differentiation

Derivatives
Derivative Notation

Basic Power Rule:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Derivative Rule [Quotient Rule]: $\displaystyle \frac{d}{dx} [\frac{f(x)}{g(x)} ]=\frac{g(x)f'(x)-g'(x)f(x)}{g^2(x)}$

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify</em>

$\displaystyle f(x) = \frac{\sqrt{x}}{e^x}$

<u>Step 2: Differentiate</u>

Derivative Rule [Quotient Rule]: $\displaystyle f'(x) = \frac{(\sqrt{x})'e^x - \sqrt{x}(e^x)'}{(e^x)^2}$
Basic Power Rule: $\displaystyle f'(x) = \frac{\frac{e^x}{2\sqrt{x}} - \sqrt{x}(e^x)'}{(e^x)^2}$
Exponential Differentiation: $\displaystyle f'(x) = \frac{\frac{e^x}{2\sqrt{x}} - \sqrt{x}e^x}{(e^x)^2}$
Simplify: $\displaystyle f'(x) = \frac{\frac{e^x}{2\sqrt{x}} - \sqrt{x}e^x}{e^{2x}}$
Rewrite: $\displaystyle f'(x) = \bigg( \frac{e^x}{2\sqrt{x}} - \sqrt{x}e^x \bigg) e^{-2x}$
Factor: $\displaystyle f'(x) = \bigg( \frac{1}{2\sqrt{x}} - \sqrt{x} \bigg)e^\big{-x}$

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Differentiation

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3 years ago

Round 1.963 to the nearest tenth

faust18 [17]

Answer:

Step-by-step explanation:

1.963 to the nearest tenth is 2.0 or 2

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3 years ago