Volume of a quadrangular pyramid=(1/3)bh
b=base
h=height
b=area of the base=area of a square=8.4 ft * 8.4 ft=70.56 ft²
Pythagoras theorem:
hypotenuse²=leg₁² + leg₂²
data:
hypotenuse=9.6 ft
leg₁=height=h
leg₂=8.4 ft /2=4.2 ft
(9.6 ft)²= h² + (4.2 ft)²
92.16 ft²=h²+17.64 ft²
h²=92.16 ft²-17.64 ft²
h²=74.52 ft²
h=√(74.52 ft²)=8.63 ft.
Volume of this quadrangular pyramid=(1/3)(70.56 ft²)(8.63 ft)=202.9 ft³≈202.3 ft³
Answer: ≈202.3 ft³
SA: 2pi (r^2)+2pi(r)(h)
In order to find radius (r) of the base you must divide 10 by pi then find the square root of the result
√(10/pi)=r: 1.784cm
h: a) 8.0cm
b) 6.5cm
c) 9.4cm
2pi (3.183)+2pi(1.784)(8)=109.673cm^2
2pi (3.183)+2pi(1.784)(6.5)=92.859cm^2
2pi (3.183)+2pi(1.784)(9.4)=125.366cm^2
Answer:
9.42 i think
Step-by-step explanation:
Answer:
x = 2 11/12
Step-by-step explanation:
Multiply the equation by 12. This eliminates fractions.
... 12 -12x -28 = 12x +27 -36x -8
Collect terms.
... -16 -12x = -24x +19
Add 24x+16
... 12x = 35
Divide by the coefficient of x
... x = 35/12 = 2 11/12
The lengths of the other two sides of the right triangle are 12 and 13
<h3>Pythagorean theorem </h3>
From the question, we are to determine the lengths of the other sides of the triangle
From the given information,
The other sides have lengths that are consecutive integers
Thus,
If the length of the other side is x
Then,
The hypotenuse will be x + 1
By the <em>Pythagorean theorem</em>, we can write that
(x+1)² = x² + 5²
(x+1)(x+1) = x² + 25
x² + x + x + 1 = x² + 25
x² - x² + x + x = 25 - 1
2x = 24
x = 24/2
x = 12
∴ The other leg of the right triangle is 12
Hypotenuse = x + 1 = 12 + 1 = 13
Hence, the lengths of the other two sides are 12 and 13
Learn more on Pythagorean theorem here: brainly.com/question/4584452
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