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3 years ago

Find the greatest common factor of 15x^2y^3 and -18x^3yz The Answer has to be like _x_y_

Mathematics

1 answer:

Daniel [21]3 years ago

8 0

Answer:

The greatest common factor of this would be 3x^2y

Step-by-step explanation:

In order to find this, first find the greatest common factor of the coefficients. Since 3 goes in evenly to both 15 and -18, then we know that it is a common factor.

From there we need to find the number of x's. Since the first term only has 2 x's and the second has 3, we take the lowest number. (x^2)

And since the first term has 3 y's and the second has just 1, we take the lowest number (y).

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41. Consider the perimeter of the triangle shown. First, find the length of the hypotenuse.

marysya [2.9K]

Use the Pythagorean theorem!

This principle applies to any right triangles.

This states the relationship between the sides that

(7)² + (24)² = x²

All you have to do is simplify at this point.

49 + 576 = x²

625 = x²

√ √

x = 25

You should try to memorize this right triangle. It can be very helpful in fast questionnaires, such as the SAT.

6 0

2 years ago

Read 2 more answers

When cooking a certain type of rice, the ratio of water to rice should always be 3 to 2. The table below shows this relationship

Komok [63]

Answer/Step-by-step explanation:

3:2 = 6:4 = 15:10

Check work:

3 ÷ 2 = 1.5

6 ÷ 4 = 1.5

15 ÷ 10 = 1.5

5 0

2 years ago

Translate the sentence into an equation.

coldgirl [10]

Hey there!

We want to multiply a certain quantity by 2, so we will put the two outside of parentheses and put our variable (x) minus two inside the parentheses to represent this. This will all equal two.

2(x-6)=2

The unknown number is also 7.

I hope that this helps!

7 0

3 years ago

Sofia hits a softball straight up. the equation h= -16t^2 + 90t models the height h, in feet, of the ball after t seconds. How l

andrezito [222]

It is in the air 5.625 seconds.

Using the quadratic formula,

$t=\frac{-b\pm \sqrt{b^2-4ac}}{2a}
\\
\\=\frac{-90\pm \sqrt{90^2-4(-16)(0)}}{2(-16)}
\\
\\=\frac{-90\pm \sqrt{8100-0}}{-32}
\\
\\=\frac{-90\pm \sqrt{8100}}{-32}=\frac{-90\pm90}{-32}
\\
\\=\frac{-90+90}{-32}\text{ or }\frac{-90-90}{-32}=\frac{0}{32}\text{ or }\frac{-180}{-32}
\\
\\=0\text{ or }5.625$

0 is when the ball is first launched, 5.625 is when it hits the ground again.

4 0

3 years ago

FRAME AN EQUATION AND SOLVE IT. NEED HELP ASAP I only have 5 minutes!

lawyer [7]

Answer:

The answer to your question is 125

Step-by-step explanation:

x = 25 X 5= 125.

The required number is 125.

I hope this helps and have a good day!

3 0

2 years ago