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Zigmanuir [339]
3 years ago
12

Which polynomial is in standard form? a)2xy^3 +3x^3 y^4 -4x^4 y^5 +9x^5 y^6 b)8x^5 -5y^4 -2xy^5 + x^2 y c)x^3 y^2 -3x^2 y-9x^4 y

^3 +11x d)5x^7 y^2 + 7x^6 y^5 -14x^3 y^7 +51x^2 y^9
Mathematics
1 answer:
Serhud [2]3 years ago
4 0

Answer:

d) 5x^7 y^2 + 7x^6 y^5 -14x^3 y^7 +51x^2 y^9

Step-by-step explanation:

A polynomial is said to be in standard form if its terms are arranged in order of decreasing degree. That is the first term is of highest degree followed by the second term then the third term and so on. The terms of a standard polynomial are ordered from highest degree to lowest degree.

The polynomial 5x^7 y^2 + 7x^6 y^5 -14x^3 y^7 +51x^2 y^9 is in standard form because the degree of x are arranged from highest degree to lowest degree.

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Add and subtract the rational expressions. 7x+5/x-1 -(8x1/x-1+2x-4/x-1) Which statements are true about the process for adding a
anzhelika [568]

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4. The numerator of the fully simplified expression will be –3x + 10.

Step-by-step explanation:

Given the rational expression

\dfrac{7x+5}{x-1} -(\dfrac{8x-1}{x-1} +\dfrac{2x-4}{x-1} )

Let us first simplify before making our deductions.

Opening the brackets

\dfrac{7x+5}{x-1} -(\dfrac{8x-1}{x-1} +\dfrac{2x-4}{x-1} )=\dfrac{7x+5}{x-1} -\dfrac{8x-1}{x-1} -\dfrac{2x-4}{x-1}

Taking LCM

=\dfrac{7x+5-(8x-1)-(2x-4)}{x-1}

Opening the brackets and simplifying

=\dfrac{7x+5-8x+1-2x+4}{x-1}\\\text{Collecting like terms in the numerator}\\=\dfrac{7x-8x-2x+5+1+4}{x-1}\\=\dfrac{-3x+10}{x-1}

The following statements are therefore true:

2. The denominator of the fully simplified expression will be x – 1.

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