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kompoz [17]
3 years ago
12

!!!PLEASE HELPPPPPP ILL DO WHATEVER!!! ILL GIVE >>BRAINLIEST<

Mathematics
1 answer:
Rufina [12.5K]3 years ago
3 0

Answer:

x >2.2034

Step-by-step explanation: hope this helps :)

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In the figure, the slope of mid-segment DE is -0.4. The slope of segment AC is?
chubhunter [2.5K]

Answer:

\pink{\boxed{{\colorbox{white}{Answer}}}}

\purple {\overline{ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: }}

In the figure, the slope of mid-segment DE is -0.4. The slope of segment AC is?

A.) 0.4

B.) -0.4

C.) 2

D.) -2

\purple {\overline{ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: }}

Step-by-step explanation:

\pink{\boxed{{\colorbox{white}{- MsTiyana}}}}

# i hope it helps you

# mark me brainliest thank you

8 0
2 years ago
Please help question in picture please
VikaD [51]

Answer:

<em>-1,3,5,9,13</em>

Step-by-step explanation:

2(-3)+5=-6+5=-1

2(-1)+5=-2+5=3

2(0)+5=0+5=5

2(2)+5=4+5=9

2(4)+5=8+5=13

7 0
3 years ago
What is the correct line graph for y=3x+5?
AysviL [449]

Answer:

The equation y=−3x+5 is in slope intercept form, and represents a straight line in which -3 is the slope, and 5 is the y -intercept.

3 0
3 years ago
If an angle is obtuse what type of angle is its supplement
Butoxors [25]
The supplement of an obtuse angle is an acute because the angle number for an obtuse angle is any number greater than 90 degrees. So an acute angle is less than 90 degrees. The "supplement" definition is "any number less than 180 degrees." 

Hope this helps, 

kwrob
3 0
3 years ago
A=1/2bh for b<img src="https://tex.z-dn.net/?f=a%3D1%2F2bh%20for%20b" id="TexFormula1" title="a=1/2bh for b" alt="a=1/2bh for b"
valkas [14]
Times both sides by 2
2A=bh
divide both sides b h
\frac{2A}{h}=b
b=\frac{2A}{h}
5 0
3 years ago
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