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vladimir1956 [14]
4 years ago
11

The area of a rectangle is 56 cm. The length is 2 cm more than x and the width is 5 cm less than twice x. Solve for x. Round to

the nearest whole number.
Mathematics
1 answer:
vovikov84 [41]4 years ago
4 0
56=(x+2)x(2x-5)
56=2x^2-5x+4x-10
56=2x^2-x-10
0=2x^2-x-66(use midterm breaking now)
0=2x^2+11x-12x-66
0=2x(x-6)+11(x-6)
So factors are (2x+11) or (x-6) as the length is always positive we chose x-6 so x-6=0..x=6 is the answer thanks now plz select answer as brainliest :)
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Nookie1986 [14]

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Part A) The graph in the attached figure (see the explanation)

Part B) The ordered pair is a solution of the system of inequalities (is included in the solution area for the system)

Step-by-step explanation:

Part 1) Graph the system of inequalities

we have

y> 5x+5 ----> inequality A

The solution of the inequality A is the shaded area above the dashed line y=5x+5

The slope pf the dashed line A is positive m=5

The y-intercept of the dashed line A is (0,5)

The x-intercept of the dashed line A is (-1,0)

y>-\frac{1}{2}x+1 ----> inequality B

The solution of the inequality B is the shaded area above the dashed line y=-\frac{1}{2}x+1

The slope pf the dashed line B is negative m=-1/2

The y-intercept of the dashed line B is (0,1)

The x-intercept of the dashed line B is (2,0)

The solution of the system of inequalities is the shaded area above the dashed line A and above the dashed line B

using a graphing tool

see the attached figure

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we know that

If a ordered pair is a solution of the system of inequalities, then the ordered pair must satisfy both inequalities

substitute the value of x and the value of y in each inequality

For x=-2, y=5

<em>Verify inequality A</em>

5>5(-2)+5

5>-5 ---> is true

so

The ordered pair satisfy inequality A

<em>Verify inequality B</em>

5>-\frac{1}{2}(-2)+1

5>2 ---> is true

so

The ordered pair satisfy inequality B

therefore

The ordered pair is a solution of the system of inequalities (is included in the solution area for the system)

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