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3 years ago

8

A mosquito collides head-on with a car traveling 60 mph. Is the force of the mosquito on the car larger than, smaller than, or e

qual to the force of the car on the mosquito? Explain.

1 answer:

nirvana33 [79]3 years ago

5 0

Smaller the mosquitoes possibly fly only 9mph a car coming at 60 would destroy mosquito obviously the force of a moving object will move it

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Please help, basic Algebra question

Tju [1.3M]

Answer:

The given expression $(\frac{5}{6} a^{9}p^{5}) ^{3} = \frac{125}{216} \times a^{(27) } \times p^{(15)}$

Step-by-step explanation:

Here, the given expression is: $(\frac{5}{6} a^{9}p^{5}) ^{3}$

Now, starting from the outer most bracket.

As we know :

$(abc)^{n} = (a)^{n} \times (b)^{n} \times (c)^{n}$

and $(a^m)^{n} = a^{(m \times n)}$

⇒ $(\frac{5}{6} a^{9}p^{5}) ^{3} = (\frac{5}{6})^{3} \times (a^{9})^{3} \times (p^{5}) ^{3}\\$

$=\frac{125}{216} \times (a)^{(9\times3) } \times (p)^{(5 \times 3)}\\= \frac{125}{216} \times a^{(27) } \times p^{(15)}$

Hence, the given expression $(\frac{5}{6} a^{9}p^{5}) ^{3} = \frac{125}{216} \times a^{(27) } \times p^{(15)}$

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LekaFEV [45]

The answer would be the first person said 6, -26,102

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2 years ago

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o-na [289]

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the sum of −2x2 + x + 31 and 3x2 + 7x − 8 can be written in the form ax2 + bx + c, where a, b, and c are constants. What is the

Kitty [74]

Answer:

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Step-by-step explanation:

we have

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Adds the terms

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Neko [114]

32 square root 6
use the pythagoream theorum
the sides would be 32 and 16. 16^2+x^2=32^2

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