URGENT! Please help me find the total area of this house.

How many pairs of whole numbers have the Sum of 12

nataly862011 [7]

Thanks for the question!

Don't forget 0 is a whole number:

0 + 12
1 + 11
2 + 10
3 + 9
4 + 8
5 + 7
6 + 6

Hope this helps!

8 0

3 years ago

What is the value of the discriminant, b2 − 4ac, for the quadratic equation 0 = x2 − 4x + 5, and what does it mean about the num

forsale [732]

(-4)^2-4(1)(5)
16-4(1)(5)
16-4(5)
16-20
-4

The discriminant is negative so there are no real number solutions.

3 0

3 years ago

Read 2 more answers

Factorize: 3a^2 + 10a + 3

sergey [27]

Answer: (3a + 1) (a + 3)

Step-by-step explanation:

Concept:

Here, we need to know the idea of factorization.

It is like "splitting" an expression into a multiplication of simpler expressions. Factoring is also the opposite of Expanding.

Solve:

Given = 3a² + 10a + 3

STEP ONE: separate 3a² into two terms

3a

a

STEP TWO: separate 3 into two terms

3

1

STEP THREE: match the four terms in ways that when doing cross-multiplication, the result will give us 10a.

3a 1

a 3

When cross multiply, 3a × 3 + 1 × a = 10a

STEP FOUR: combine the expression horizontally to get the final factorized expression.

3a ⇒ 1

a ⇒ 3

(3a + 1) (a + 3)

Hope this helps!! :)

Please let me know if you have any questions

7 0

3 years ago

The line x = 6 is: A. Cannot be determined B. Horizontal C. Neither D. Vertical

jeka94

Answer:

Vertical

Step-by-step explanation:

Vertical line crossing the x-axis at 6. It does not cross the y-axis.

6 0

4 years ago

Triangle ABC has vertices at A(2,3),B(-4,-3) and C(2,-3) find the coordinates of each point of concurrency.

dem82 [27]

Answer:

Circumcenter =(-1,0)

Orthocenter =(2,-3)

Step-by-step explanation:

Given : Points A = (2,3), B = (-4,-3), C = (2,-3)

Formula used :

→Mid point of two points- $(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})$

→Slope of two points - $\frac{y_2-y_1}{x_2-x_1})$

→Perpendicular of a line = $\frac{-1}{slope of line})$

Circumcenter- The point where the perpendicular bisectors of a triangle meets.

Orthocenter-The intersecting point for all the altitudes of the triangle.

To find out the circumcenter we have to solve any two bisector equations.

We solve for line AB and AC

So, mid point of AB = $(\frac{2-4}{2},\frac{3-3}{2})=(-1,0)$

Slope of AB = $\frac{-3-3}{-4-2}=1$

Slope of the bisector is the negative reciprocal of the given slope.

So, the slope of the perpendicular bisector = -1

Equation of AB with slope -1 and the coordinates (-1,0) is,

(y – 0) = -1(x – (-1))

y+x=-1………………(1)

Similarly, for AC

Mid point of AC = $(\frac{2+2}{2},\frac{3-3}{2})=(2,0)$

Slope of AC = $\frac{-3-3}{2-2}=\frac{-6}{0}$

Slope of the bisector is the negative reciprocal of the given slope.

So, the slope of the perpendicular bisector = 0

Equation of AC with slope 0 and the coordinates (2,0) is,

(y – 0) = 0(x – 2)

y=0 ………………(2)

By solving equation (1) and (2),

put y=0 in equation (1)

y+x=-1

0+x=-1

⇒x=-1

So the circumcenter(P)= (-1,0)

To find the orthocenter we solve the intersections of altitudes.

We solve for line AB and BC

So, mid point of AB = $(\frac{2-4}{2},\frac{3-3}{2})=(-1,0)$

Slope of AB = $\frac{-3-3}{-4-2}=1$

Slope of the bisector is the negative reciprocal of the given slope.

So, the slope of CF = -1

Equation of AB with slope -1 and the coordinates (-1,0) gives equation CF

(y – 0) = -1(x – (-1))

y+x=-1………………(3)

Similarly, mid point of BC = $(\frac{-4+2}{2},\frac{-3-3}{2})=(-1,-3)$

Slope of AB = $\frac{-3+3}{-4-2}=0$

Slope of the bisector is the negative reciprocal of the given slope.

So, the slope of AD = 0

Equation of AB with slope 0 and the coordinates (-1,-3) gives equation AD

(y-(-3)) = 0(x – (-1))

y+3=0

y=-3………………(4)

Solve equation (3) and (4),

Put y=-3 in equation (3)

y+x=-1

-3+x=-1

x=2

Therefore, orthocenter(O)= (2,-3)

7 0

3 years ago