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3 years ago

X-(-10)=-20 what is the answere?

Mathematics

1 answer:

MissTica3 years ago

8 0

Answer:

x = -30

Step-by-step explanation:

x - (-10) = -20

Subtracting a negative is adding

x+10 = -20

Subtract 10 from each side to isolate x

x+10-10 = -20-10

x = -30

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36.2 rounding to the nearest tenth

guapka [62]

This is what I found

Step-by-step explanation: To round 36.2 to the nearest tenth consider the hundredths' value of 36.2, which is 0 and equal or more than 5. Therefore, the tenths value of 36.2 increases by 1 to 3.

7 0

3 years ago

How do u do find vertices of dilation if the factor is k =3

VladimirAG [237]

Do you have a graph or a picture? It would be easier to explain

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3 years ago

The weekly amount spent by a small company for in-state travel has approximately a normal distribution with mean $1450 and stand

Llana [10]

Answer:

0.0903

Step-by-step explanation:

Given that :

The mean = 1450

The standard deviation = 220

sample mean = 1560

$P(X > 1560) = P( Z > \dfrac{x - \mu}{\sigma})$

$P(X > 1560) = P(Z > \dfrac{1560 - 1450}{220})$

$P(X > 1560) = P(Z > \dfrac{110}{220})$

P(X> 1560) = P(Z > 0.5)

P(X> 1560) = 1 - P(Z < 0.5)

From the z tables;

P(X> 1560) = 1 - 0.6915

P(X> 1560) = 0.3085

Let consider the given number of weeks = 52

Mean $\mu_x$ = np = 52 × 0.3085 = 16.042

The standard deviation = $\sqrt {n \time p (1-p)}$

The standard deviation = $\sqrt {52 \times 0.3085 (1-0.3085)}$

The standard deviation = 3.3306

Let Y be a random variable that proceeds in a binomial distribution, which denotes the number of weeks in a year that exceeds $1560.

Then;

Pr ( Y > 20) = P( z > 20)

$Pr ( Y > 20) = P(Z > \dfrac{20.5 - 16.042}{3.3306})$

$Pr ( Y > 20) = P(Z >1 .338)$

From z tables

P(Y > 20) $\simeq$ 0.0903

7 0

3 years ago

Edna decided to purchase a $15,000 MSRP vehicle at a 5% interest rate for 3 years. The dealership offered her a $1500 cash-back

Ad libitum [116K]

P = A/D, Where P = Monthly payments, A = Total amount owed = 15,000-1,500 = $13,500,

$D= \frac{( 1+ \frac{r}{12} )^{nt} -1}{ \frac{r}{12} (1+ \frac{r}{12}) ^{nt} }$

r = 5% = 0.05, nt = 12*3 = 36

Therefore,
D = $\frac{(1+ 0.05/12)^{36}-1 }{(0.05/12)(1+0.05/12)^{36} }$ = 33.37

Then,

P = 13,500/44.37 = $404.61
The correct answer is c.

5 0

3 years ago

A box contains four $1 and six $5 bills. if three bills are selected at random without replacement, find the probability that al

myrzilka [38]

Answer:

C.1/6

Step-by-step explanation:

Initially the box has four $1 and six $5 bills. The probability of selecting a $5 bill in the first trial would be given as;

(number of $5 bills) / (total number of bills)

= (6)/(4+6) = 3/5

If in the first attempt we actually pick a $5 bill, the number of $5 bills will reduce by one to 5. Now, the probability of picking a $5 bill in the second attempt will be given as;

(new number of $5 bills) / (new total number of bills)

= (5)/(4+5) = 5/9

The new number of $5 bills will now be; 6 - 2 = 4 since we have already picked 2 without replacing them.

Now, the probability of picking a $5 bill in the third attempt will be given as;

(new number of $5 bills) / (new total number of bills)

= (4)/(4+4) = 1/2

Since the three attempts are independent, the probability of picking all three $5 bills is;

3/5 * 5/9 * 1/2 = 1/6

7 0

3 years ago