The answer is y=10/7-5/7x, subtract the 5x and put it on the other side then divide the 7 from the y and divide it to 10-5x to get the answer.
Let's represent the two numbers by x and y. Then xy=60. The smaller number here is x=y-7.
Then (y-7)y=60, or y^2 - 7y - 60 = 0. Use the quadratic formula to (1) determine whether y has real values and (2) to determine those values if they are real:
discriminant = b^2 - 4ac; here the discriminant is (-7)^2 - 4(1)(-60) = 191. Because the discriminant is positive, this equation has two real, unequal roots, which are
-(-7) + sqrt(191)
y = -------------------------
-2(1)
and
-(-7) - sqrt(191)
y = ------------------------- = 3.41 (approximately)
-2(1)
Unfortunately, this doesn't make sense, since the LCM of two numbers is generally an integer.
Try thinking this way: If the LCM is 60, then xy = 60. What would happen if x=5 and y=12? Is xy = 60? Yes. Is 5 seven less than 12? Yes.
Answer:
After one year the population will be 33 deers, and after two years it will be 36 deers.
Step-by-step explanation:
Given that a population of 30 deer is introduced into a wildlife sanctuary, and it is estimated that the sanctuary can sustain up to 200 deer, and absent constraints, the population would grow by 10% per year, to predict the population after one year and after two years, the following calculations must be performed:
A)
30 x 1.1 = X
33 = X
B)
30 x 1.1 ^ 2 = X
30 x 1.21 = X
36.3 = X
Therefore, after one year the population will be 33 deers, and after two years it will be 36 deers.
Answer:
B. 624
Step-by-step explanation:
P = ρgh
P = (62.4 lb/ft³) (10 ft)
P = 624 lb/ft²
Part A: 40/100 = 0.4 0.4*36=14 14 + 36=50 Part B :40/100=0.4 0.4*60=24 60+24=84
hope this helped
