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3 years ago

Which is smaller 8.0 .08 .008 .80?

1 answer:

lina2011 [118]3 years ago

6 0

.008 is the smallest. 8.0 is referring to 8 wholes, .80 is referring to 8 out of 10 pieces, and .08 is referring to 8 out of 100. However, .008 is referring to 8 out of 1000, which is extremely small.

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Find the values of the variables in each right triangle.

Masteriza [31]

Answer:

x = 12

y = 16

Step-by-step explanation:

Use the Pythagoras Theorem on the left triangle.

$(Hypotenuse)2=(Base)^2+(Perpendicular)^2\\(x)^2=(7.2)^2+(9.6)^2\\x^2=51.84+92.16\\x^2=144\\x=\sqrt{144}\\x=12\\$

Now use the Pythagoras Theorem on the right triangle.

$(Hypotenuse)2=(Base)^2+(Perpendicular)^2\\(y)^2=(12.8)^2+(9.6)^2\\y^2=163.84+92.16\\y^2=256\\y=\sqrt{256}\\y=16\\$

4 0

3 years ago

If the length of a rectangle is 5 m more than its width find the values of length and width if the area of a rectangle is 500 m²

astra-53 [7]

Answer:

Length of the rectangle =25

width of the rectangle = 20

Step-by-step explanation:

Step(i):-

Let 'x' be the width of the rectangle

Given that the length of a rectangle is 5 m more than its width

Given that Area of the rectangle = 500m²

length of a rectangle = x +5

width of a rectangle = x

Step(ii):-

Area of the rectangle = length × width

500 = x ( x+5)

x² + 5 x = 500

⇒ x² + 5 x - 500 =0

⇒ x² +25x - 20 x - 500 =0

⇒ x( x+25) -20(x+25) =0

⇒ (x-20)(x+25) =0

⇒ x =20 and x=-25

we can choose x =20

Step(iii):-

Length of the rectangle = x +5 = 20 +5 =25

width of the rectangle = 20

Final answer:-

Length of the rectangle =25

width of the rectangle = 20

3 0

3 years ago

What’s the answer in simplified form

Schach [20]

Answer:

Step-by-step explanation:

To solve this correctly, you need to make sure to distribute the negative onto both terms in the second parentheses.

So fully expanded, the problem would be:

2y² + 8y -7 + 3y - 3 = ?

You can easily rearrange the terms, or just do it in your head!

It would become:

2y² + 8y +3y -7 -3

= 2y² + 11y -10

Make sure you keep the terms with different variables separate! I hope this is helpful!

3 0

3 years ago

1. Iris has two ribbons. The first ribbon is 11.7 in. long. The second ribbon is 5.25 in. long. She wants to cut them so that th

lisov135 [29]

The estimated lengths are 12in. and 5 in. This would be an estimated difference of 7in.

The estimated difference is going to be higher than the actual difference because in rounding 11.7 to 12, you are losing .30in, but in rounding down 5.25 to 5, you are actually gaining .75in.

The ACTUAL difference is 6.45in

3 0

3 years ago

Use the Distributive Property to simplify the expression 4(c - 2)

xeze [42]

Answer

Step-by-step explanation:

4xc=4c

4x-2= -8

4c-8

3 0

3 years ago