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iragen [17]
3 years ago
10

John Maynord pays a $566.00 annual insurance premium. This represents 40% of the total premium. The rest of the premium is paid

by his employer. Calculate:
. the company's percentage
. the total premium
. the company's payment
Mathematics
2 answers:
Aleksandr-060686 [28]3 years ago
6 0
60%
$1415
$849
Hope this helps
baherus [9]3 years ago
6 0

Answer:

A. 60%

B. $1415

C. $849.

Step-by-step explanation:

We have been given that  John Maynord pays a $566.00 annual insurance premium. This represents 40% of the total premium. The rest of the premium is paid by his employer.

A. Since John pays 40% of his premium and rest of the premium is paid by his employer. This means that his employer pays 60% (100-40) of the premium, therefore, the company's percentage will be 60%.

B. Let x be the total amount of the premium.

As 40% of the premium is $566, so we need to find x such that 40% of x is $566.

We can represent this information in an equation as:

\frac{40}{100}*x=\$566

0.40*x=\$566

\frac{0.40*x}{0.40}=\frac{\$566}{0.40}

x=\$1415

Therefore, the total amount of premium is $1415.

C. As company pays 60% of premium, so to find the company's payment we will find 60% of $1415.

\text{The company's payment}=\frac{60}{100}*\$1415

\text{The company's payment}=0.60*\$1415

\text{The company's payment}=\$849

Therefore, the company's payment is $849.

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\begin{gathered} f(x)=\frac{x+12}{x^2+4x-12}=\frac{x+12}{x^2+6x-2x-12}=\frac{x+12}{x(x+6)-2(x+6)}=\frac{x+12}{(x-2)(x+6)} \\ f(x)=\frac{x+12}{(x-2)(x+6)} \end{gathered}

Factorising the denominator of g(x),

\begin{gathered} g(x)=\frac{4x^2-16x+16}{4x+48}=\frac{4(x^2-4x+4)}{4(x+12)} \\ \text{Cancel out 4 from both numerator and denominator} \\ g(x)=\frac{x^2-4x+4}{x+12}=\frac{x^2-2x-2x+4}{x+12}=\frac{x(x-2)-2(x-2)}{x+12}=\frac{(x-2)^2}{x+12} \\ g(x)=\frac{(x-2)^2}{x+12} \end{gathered}

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undefined

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Answer:

a) 1.

Step-by-step explanation:

Supongamos que el primer número entero positivo es a tal que a ∈ Z⁺.

Luego, el conjunto de los cinco enteros positivos se puede expresar como

A = {a; a+1; a+2; a+3; a+4}

Dada la condición del problema, se debe cumplir que

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Luego, el conjunto A nos resulta

A = {4; 5; 6; 7; 8}

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